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lianna [129]
2 years ago
8

There are 5/6 jugs of water and 3/10 of the water are for the other runners. How many jugs of water is there

Mathematics
1 answer:
Whitepunk [10]2 years ago
8 0

Answer:

8/15 left

Step-by-step explanation:

Given data

We want to perform subtraction operation on fractions

Total number of water= 5/6

we are told that 3/10 are for other runners

Hence the number of water left is

=5/6-3/10

=50-18/60

=32/60

=8/15

Hence there are 8/15 left

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128.34=12817/50 THAT IS THE ANSWER FOR THIS QUESTION

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Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
3 years ago
3) There were 35 children and 10 adults at a barbeque.
Mila [183]

Answer:

3. a. 10:35= 2:7

b.35:45=7:9

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7 0
3 years ago
two men A and B stand on opposite sides of a 100 metre tower.A observes the angle of elevation of the top of the tower as 45 and
Zepler [3.9K]

9514 1404 393

Answer:

  273 m

Step-by-step explanation:

The tower represents the short side of a 30°-60°-90° right triangle. The distance from the tower represents the long leg, not the hypotenuse, of that triangle. It is √3 times the short side. In this geometry, man B is 100√3 = 173.2 meters from the tower.

The tower represents one of two congruent sides of a 45°-45°-90° right triangle. Man A will be standing 100 meters from the tower.

The distance between A and B is 100 +173.2 = 273.2 meters. The men are about 273 meters apart.

8 0
3 years ago
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