All categories

2 years ago

There are 5/6 jugs of water and 3/10 of the water are for the other runners. How many jugs of water is there

Mathematics

1 answer:

Whitepunk [10]2 years ago

8 0

Answer:

8/15 left

Step-by-step explanation:

Given data

We want to perform subtraction operation on fractions

Total number of water= 5/6

we are told that 3/10 are for other runners

Hence the number of water left is

=5/6-3/10

=50-18/60

=32/60

=8/15

Hence there are 8/15 left

You might be interested in

Graphing using the y intercept and slope: y = - 3x + 5 b(y - intercept) = m(slope) =

babymother [125]

The answer is 3x- I just took the text

6 0

2 years ago

128.34 as a mixed number in simplest form

KonstantinChe [14]

128.34=12817/50 THAT IS THE ANSWER FOR THIS QUESTION

4 0

3 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

3 years ago

3) There were 35 children and 10 adults at a barbeque.

Mila [183]

Answer:

3. a. 10:35= 2:7

b.35:45=7:9

c.40:50=4:5

7 0

3 years ago

two men A and B stand on opposite sides of a 100 metre tower.A observes the angle of elevation of the top of the tower as 45 and

Zepler [3.9K]

9514 1404 393

Answer:

273 m

Step-by-step explanation:

The tower represents the short side of a 30°-60°-90° right triangle. The distance from the tower represents the long leg, not the hypotenuse, of that triangle. It is √3 times the short side. In this geometry, man B is 100√3 = 173.2 meters from the tower.

The tower represents one of two congruent sides of a 45°-45°-90° right triangle. Man A will be standing 100 meters from the tower.

The distance between A and B is 100 +173.2 = 273.2 meters. The men are about 273 meters apart.

8 0

3 years ago