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3 years ago

EPCIUCNO

Mathematics

1 answer:

cluponka [151]3 years ago

4 0

Answer:

1 ⇒ D

2 ⇒ H

3 ⇒ B

4 ⇒ G

5 ⇒ A

6 ⇒ F

7 ⇒ E

8 ⇒ C

Step-by-step explanation:

* Lets explain how to solve the problem

- The left column has expressions and the right column has the

equivalent expressions

- We must find the equivalent letter for each number

# 7(12)

∵ 12 can be a sum of two numbers

∴ The equivalent expression to 7(12) is 7(8 + 4)

∴ 1 ⇒ D

# 3(15)

∵ 3 can be a sum of two numbers

∴ The equivalent expression to 3(15) is (2 + 1)(15)

∴ 2 ⇒ H

# 3a + 9

∵ 3 and 9 have a common factor 3

∵ 3a + 9 ⇒ divide them by 3

∵ 3a ÷ 3 = a and 9 ÷ 3 = 3

∴ 3a + 9 = 3(a + 3)

∴ The equivalent expression to 3a + 9 is 3(a + 3)

∴ 3 ⇒ B

# 9a + 3

∵ 9 and 3 have a common factor 3

∵ 9a + 3 ⇒ divide them by 3

∵ 9a ÷ 3 = 3a and 3 ÷ 3 = 1

∴ 9a + 3 = 3(3a + 1)

∴ The equivalent expression to 9a + 3 is 3(3a + 1)

∴ 4 ⇒ G

# 5 + 15a

∵ 5 and 15 have a common factor 5

∵ 5 + 15a ⇒ divide them by 5

∵ 5 ÷ 5 = 1 and 15a ÷ 5 = 3a

∴ 5 + 15a = 5(1 + 3a)

∴ The equivalent expression to 5 + 15a is 5(1 + 3a)

∴ 5 ⇒ A

# 10 + 5a

∵ 10 and 5 have a common factor 5

∵ 10 + 5a ⇒ divide them by 5

∵ 10 ÷ 5 = 2 and 5a ÷ 5 = a

∴ 10 + 5a = 5(2 + aa)

∴ The equivalent expression to 10 + 5a is 5(2 + a)

∴ 6 ⇒ F

# 3x + 6y + 9z

∵ The coefficient of x , y , z have a common factor 3

∵ 3x ÷ 3 = x

∵ 6y ÷ 3 = 2y

∵ 9z ÷ 3 = 3z

∴ 3x + 6y + 9z = 3(x + 2y + 3z)

∴ The equivalent expression to 3x + 6y + 9z is 3(x + 2y + 3z)

∴ 7 ⇒ E

# 3x + 3y + 3z

∵ The coefficient of x , y , z have a common factor 3

∵ 3x ÷ 3 = x

∵ 3y ÷ 3 = y

∵ 3z ÷ 3 = z

∴ 3x + 3y + 3z = 3(x + y + z)

∴ The equivalent expression to 3x + 3y + 3z is 3(x + y + z)

∴ 8 ⇒ C

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$=\frac{e^{-4}4^{5}}{5!}\times [{5\choose 2}\times(\frac{3}{4})^{2}\times (\frac{1}{4})^{5-2}]\\=0.1563\times [10\times 0.5625\times 0.015625]\\=0.01374$

Thus, the probability that in one hour exactly two men and three women will call the answering service is 0.01374.

(b)

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The random variable Z is defined as the number of failures before a fixed number of successes (z) . That is, the number of calls made by men before a specific number of women made the calls.

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