The following information will help us with this problem:
![\sqrt[m]{x^n} = x^{\frac{n}{m}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Bx%5En%7D%20%3D%20x%5E%7B%5Cfrac%7Bn%7D%7Bm%7D)
When we use that information in the context of this problem, we can find:
![\sqrt[4]{15^7} = 15^{\frac{7}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B15%5E7%7D%20%3D%2015%5E%7B%5Cfrac%7B7%7D%7B4%7D%7D)
Thus, a = 15, b = 7, and c = 4.
Answer:
NO
Step-by-step explanation:
Simply enter 5, 10 in the x and y boxes to get the answer.
10=6(5)-18
10=30-18
10=12
As a consequence, it isn't a feasible option.
Answer and Step-by-step explanation:
Considering the table attached.
(a) over 9.5 kg;
μ = 8
σ = 0.9
z = 9.5 - 8/0.9 ≈ 1.67
P (Z > 1.67) = 0.5 - P(0<Z<1.67) = 0.5 - 0.4525 = 0.0475
(b) at most 8.6 kg;
z = 8.6-8/0.9 ≈ 0.67
P(Z < 0.67) = 0.5 + P(0<Z<0.67) = 0.5 + 0.2486 = 0.7486
(c) between 7.3 and 9.1 kg.
z₁ = 7.3-8/0.9 ≈ -0.78
z₂ = 9.1 - 8/0.9 ≈ 1.22
P(-0.78 < Z < 1.22) = P(0 < Z < 0.78) + P(0 < Z < 1.22) = 0.2823 + 0.3888 = 0.6711
Answer:
put a picture up
Step-by-step explanation:
Function A is linear
y = 5/3x + 0
let me know if this is incorrect