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Stells [14]
3 years ago
12

Please help me get the answers. I don't understand it

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
3 0
Number 14:
When looking at the table, the x has an increase of 3 while the y is an increase of 6. We need to divide the difference of the y by the difference of x.
6/3=2
So, that means every time x changes by one, y changes by 2. At 9, the corresponding number is 15. Since we’re to 10, the corresponding number has to be 17.
So, the answer is b, 17.

Number 15:
This problem deals with perimeter. No matter what, the perimeter is 12 feet.
To find perimeter, it is 2l+2w=12
We have the length, so let’s put it in.
2(4.5)+2(w)=12
Let’s multiply.
9+2w=12
We need w by itself, so we need to subtract 9 from both sides then divide by 2.
2w=3
3/2=1.5
The answer is A, 1.5.
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What is the value for y
Dahasolnce [82]

Answer:

y = -2/5x + 24

Step-by-step explanation:

(5y + 10) + 2x + 50 = 180

5y + 2x + 60 = 180

5y + 2x = 120

5y = -2x + 120

y = -2/5x + 24

7 0
3 years ago
What’s the mean,median,mode and range
Komok [63]

Answer:

Mean=2.1

Median=2

Mode=1,2, and 3

Range=5

Step-by-step explanation:

Mean is all the numbers added up and then divided by the amount of numbers there are, so 0+1+0+2+3+1+3+5+4+2=21, and then 21 divided by 10=2.1

Median is lining all the numbers up least to greatest and then finding the middle number, which is 2.

Mode is the number that appears the most, and since 1,2,3 all appeared twice in the data, they are the mode.

Range is the highest number in the data subtracted by the lowest number in the data, so 5-0=0

(hope this helps!)

4 0
3 years ago
How can i simplify 16m cubed -10m squared
adoni [48]
16m cubed - 10m squared......
take out the common factors
they both have a two that can go into it and both have two m's you can take out
so then it becomes
2m squared(8m-5) and thats your answer (:
5 0
3 years ago
Read 2 more answers
Of the student in Tom's class, 2/3 had perfect attendance this year. Of Maya's class, 3/4 have also been at school each day. In
IRISSAK [1]
Tom=36 Maya=32 Tom= 2/3=perfect attendance 24/2= 12 12= 1/3 12x3(3/3)= 36 Maya=3/4 perfect attendance 24/3= 8 8=1/4 8x4(4/4) =32 Hope it helps :)
3 0
3 years ago
Write the equation of a hyperbola with vertices at (1,1) and (9, 1) and foci at (0, 1) and (10, 1).
Leni [432]

Answer:

Standard form of equation for a hyperbola with horizontal transverse axis:

(x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of center

For given hyperbola:

x-coordinate of center=(9+1)/2=5 (use midpoint formula)

y-coordinate of center=1

center: (5,1)

length of horizontal transverse axis=8 (from 1 to 9)=2a

a=4

 

a^2=16

..

Foci

2c=9 ( from 1 to 10)

c=4.5

..

c^2=a^2+b^2

b^2=c^2-a^2=20.25-16=4.25

..

Equation of hyperbola:

(x-5)^2/16-(y-1)^2/4.25=1

7 0
4 years ago
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