Given:
Two coins are tossed.
To find:
1. P(H on first coin)?
2. P(H on second coin)?
3. List the paired outcomes for tossing two coins.
4. How many ways are there for two coins to land?
5. What is P(HH)?
Solution:
If a a coin is tossed, then we have to possible outcomes, i.e., heads (H) and tails (T).
It is given that two coins are tossed.
1. The probability of getting a heads on first coin is:

2. The probability of getting a heads on second coin is:

3. If two coins are tossed, then the total possible outcomes are:

4. The number of ways for two coins to land is 4.
5. The probability of the heads on both tosses is:

Therefore, the required solution are:
1. 
2. 
3. List of possible outcomes is
.
4. Number of possible outcomes is 4.
5. 
Answer:
y=4x+27
Step-by-step explanation:
If a line is parallel, it would have the same slope, so you already have that.
Now, you need the y-intercept of the second line. You already have one point, so use that point and the slope to find the y-int. What you can do (since you know you have to go up 4 and over 1, add a 1 to the -5 until you get to zero. your y-int would be 7+20 since you've gone up 5x4)
your final answer (i think) should be y=4x+27, but I could be wrong :))
Answer:
A: predictions
Step-by-step explanation:
You should add the other ones
Answer:
20%
Step-by-step explanation:
First, I added them up. From the things we know, blue, red, green, yellow combined equals 16 marbles. 20-16 equals 4. So there are 4 white marbles. 4/20 times 5 equals 20/100. So the percent of the marbles that are white is 20%.