1/4 because 3 parts of the circle are coloured but 1 part is not and 3+1=4. And that leftover as a fraction is 1/4
We have <span>isosceles ∆DEK
</span><span>EF is the angle bisector of ∠E,
m∠DEF = 43°= </span><span> m∠FEK ( the bisector divide the angle in two equal angles)
</span>
so m∠DEK = m∠DEF + <span> m∠FEK = 43 + 43 = 86
</span>
<span>∆DEK is isoceles triangle (given)
</span>the two base angles are equal m∠EDK = m∠DK<span>E
</span>and the sum of angles in a triangle = 180
so m∠DEK + m∠EDK+ m∠DKE<span> = 180
86 + </span>m∠EDK+ m∠DKE = <span> 180
2 x </span><span>m∠EDK = 94
</span><span>m∠EDK = 94 / 2 = 47
</span>
in triangle DEF
m∠EDF + m∠E FD+<span>m∠FED= 180
</span>
47 +<span>m∠E FD + 4 3 = 180
</span><span>m∠E FD = 180-43-47 = 90
</span><span>Find: KF?
</span>in an isoseles triangle the bisector is in the same time median so
KF= DK / 2 = 16/ 2 = 8 cm
Jvyvub hvyub unfunny. Then a b an o
Total number of beads = 3 + 8 + 7 = 18. P(red) = total number of red/total number of beads = 3/18 = 1/6. P(blue) = total number of blue beads/total number of beads left after replacement = 8/17. P(black) = total number of black beads/total number of beads left after replacement = 7/16. Therefore P(red) = 1/6. P(blue) = 8/17. P(black) = 7/16.