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Aleonysh [2.5K]
4 years ago
6

Help please help with this question

Mathematics
2 answers:
Ulleksa [173]4 years ago
5 0
First you have to do puthagorean theorm to find the missing leg which is QR then to find sinS you go opposite over hypotenuse. simplify if needed.
siniylev [52]4 years ago
3 0
Sine is opposite/hypotenuse. Opposite of angle <em>S</em> is line <em>QR,</em> which is unknown. Therefore start with the Pythagorean Theorem to find <em>QR. </em>For simplicity, I'll use <em>x </em>as a variable for <em>QR.
</em><em> 
</em>x^{2}+60²=68²
x^{2}=68²-60²
x^{2}=4264-3600<em>
</em>x^{2}=1024
x=\sqrt{1024}
x=32

So <em>QR </em>is 32. Therefore, sin <em>S </em>is 32/68, which simplifies to 8/17.
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I dont get this one i usually know em but both anwers the same
Serga [27]

Answer:

what is the question. I'm confused

Step-by-step explanation:

6 0
2 years ago
The buyer for a chain of stores purchased lawn ornaments in bulk, paying $23 each. The stores will sell each lawn ornament for $
Naya [18.7K]

Answer:

The markup percentage is 61.2

Step-by-step explanation:

Given as :

The cost price of each ornaments = $23

The sell price of each ornament = $37.08

Let The markup percentage = x

<u>Now, According to question</u>

Markup percentage = \dfrac{s.p - c.p}{c.p} × 100

Or, x% = \dfrac{37.08 - 23}{23}

Or, x% = \dfrac{14.08}{23}

Or, x% = 0.612

∴ x = 0.612 × 100

I.e x = 61.2

So, The The markup percentage = x = 61.2

Hence, The markup percentage is 61.2 Answer

8 0
3 years ago
Joel can either work 2 days for 11 hours each day or 4 days for 6 hours each day. He takes the bus for $2.25 each way. On days h
Oxana [17]
Joel's work makes $9.50/ hr. During the 2 Day, 11 hrs shift, he earns a total of $217.55 but spends a cash of $9 on his bus. Therefore, the money left is $208.55. While on his 4 day, 6 hrs shift, he earns a total of $228 but spends $18, with a total money of $210. The option that he should take to make the most money is the 4 days for 6 hrs shift. 
7 0
3 years ago
The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
lorasvet [3.4K]

Length: 2w + 59

width: w

diagonal: (2w + 59) + 2  = 2w + 61

Length² + width² = diagonal²

(2w + 59)² + (w)² = (2w + 61)²

(4w² + 118w + 3481) + w²  = 4w² + 122w + 3721

5w² + 118w + 3481 = 4w² + 122w + 3721

w² + 118w + 3481 = 122w + 3721

w² - 4w + 3481 = 3721

w² - 4w - 240 = 0

a = 1, b = -4, c = -240

w = [-(b) +/- \sqrt{(b)^{2}  - 4(a)(c) }]/2(a)

 = [-(-4) +/- \sqrt{(-4)^{2}  - 4(1)(-240) }]/2(1)

   =  [4 +/- \sqrt{(16  + 960) }]/2        

  = [4 +/- \sqrt{(976) }]/2  

  = [2 +/- 4\sqrt{(61) }]/2  

  = 1 +/- 2\sqrt{(61) }

since width cannot be negative, disregard  1 - 2√61

w = 1 + 2√61  ≈ 16.62

Length: 2w + 59  =  2(1 + 2√61) + 59  = 2 + 4√61 + 59  =  61 + 4√61  ≈ 92.24

Answer: width = 16.62 in, length = 92.24 in

7 0
3 years ago
Draw the graphs of the equations x – y = 1 and 2x + y = 8. Shade the area bounded by these two lines and y-axis. Also, determine
NikAS [45]

Answer:

Using Geometry to answer the question would be the simplest:

Step-by-step explanation:

Remembering the formula for the area of a triangle which is A=\frac12bh. One can then tackle the question by doing the following:

Step 1 Find the y-intercepts

The y-intercepts are found by substituting in x=0.

Which gives you this when you plug it into both equations:

-y=1\\y=-1\\y=8

So the y-intercepts for the graphs are (0,-1)\\, and (0,8) respectively.

Now one has to use elimination to solve the problems by adding up the equations we get:

x-y=1\\2x+y=8\\3x=9\\x=3

Now to solve for the y component substitute:

2(3)+y=8\\y=2

Therefore, the graphs intersect at the following:

(3,2)

Now we have our triangle which is accompanied by the graph.

now to solve it we must figure out how long the base is:

b=8-(-1)\\b=9

The height must also be accounted for which is the following:

h=3

Now the formula can be used:

A=\frac12bh=\frac12(9)(3)=\frac{27}2\ \text{units}^2

7 0
3 years ago
Read 2 more answers
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