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Aleonysh [2.5K]
3 years ago
6

Help please help with this question

Mathematics
2 answers:
Ulleksa [173]3 years ago
5 0
First you have to do puthagorean theorm to find the missing leg which is QR then to find sinS you go opposite over hypotenuse. simplify if needed.
siniylev [52]3 years ago
3 0
Sine is opposite/hypotenuse. Opposite of angle <em>S</em> is line <em>QR,</em> which is unknown. Therefore start with the Pythagorean Theorem to find <em>QR. </em>For simplicity, I'll use <em>x </em>as a variable for <em>QR.
</em><em> 
</em>x^{2}+60²=68²
x^{2}=68²-60²
x^{2}=4264-3600<em>
</em>x^{2}=1024
x=\sqrt{1024}
x=32

So <em>QR </em>is 32. Therefore, sin <em>S </em>is 32/68, which simplifies to 8/17.
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Pls answer this with an explanation if you can
Nuetrik [128]

Answer:

The answer is D

Step-by-step explanation:

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LekaFEV [45]
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2 years ago
3x^2 + 4x = -8<br> solve using quadratic formula
Firdavs [7]

Use the quadratic equation to solve this (image of the quadratic equation is below)

Remember that quadratic functions are set up like so:

ax^{2} +bx +c = 0

To make the equation 3x² + 4x = -8 into a quadratic function you must bring -8 to the left side of the equation so it equals zero. To do this add 8 to both sides

3x² + 4x + 8= -8 + 8

3x² + 4x + 8 = 0

That means that in this equation...

a = 3

b = 4

c = 8

^^^Plug these numbers into the quadratic equation and solve  (Keep in mind that +/- is ± )

\frac{-4+/-\sqrt{(4)^{2}-4(3)(8)}}{2(3)}

\frac{-4+/-\sqrt{16-96}}{6}

\frac{-4+/-\sqrt{-80}}{6}

^^^There is no real solution to this equation. You must have an imaginary solution

\frac{-4+/-i\sqrt{80}}{6}

Simplify

\frac{-2+/-2i \sqrt{5}}{3}

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0
2 years ago
Amanda has a car loan for 12,000 She is paying 3% interest for 6 years. How much will she pay in interest for the 6 years
NNADVOKAT [17]
She should get
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... I hope it's right ?:)
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wariber [46]

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A cross section is a surface or shape that is exposed by making a straight cut through something especially at right angles to an axis.

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