All categories

2 years ago

HELP PLZ AND I WILL GIVE U BRAINLIEST

Mathematics

2 answers:

arsen [322]2 years ago

8 0

Answer:

Step-by-step explanation:

1. A

2. 6/10; 1/10

5's are in 10

6/10

svp [43]2 years ago

8 0

Answer:

1. A

2. 6/10; 1/10

5's are in 10

6/10

Step-by-step explanation:

Because it is (GET USE TO IT)

You might be interested in

3x+5(2+x)=4x-7 help me out here?

Oksi-84 [34.3K]

Answer:

x = -17/4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

3x + 5(2 + x) = 4x - 7

Step 2: Solve for x

[Distributive Property] Distribute 5: 3x + 10 + 5x = 4x - 7
[Addition] Combine like terms: 8x + 10 = 4x - 7
[Subtraction Property of Equality] Subtract 4x on both sides: 4x + 10 = -7
[Subtraction Property of Equality] Subtract 10 on both sides: 4x = -17
[Division Property of Equality] Divide 4 on both sides: x = -17/4

6 0

3 years ago

Read 2 more answers

Passes through (3,5) and (-1,5)

AlladinOne [14]

Presumably we're being asked for the line which passes through (3,5) and (-1,5) which is simply $y=5.$

3 0

3 years ago

What is the value of x

Afina-wow [57]

Answer:

Step-by-step explanation:

Sin(30) = LJ/8sqrt(3)

Sin 30 = ½

LJ = 4sqrt(2)

LM = JM = x

x² + x² = (4sqrt(2))²

2x² = 32

x² = 16

x = 4

6 0

3 years ago

Anyone mind helping me out?

Taya2010 [7]

hey Friend here is your answer

angle VUX

8 0

3 years ago

What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!

ipn [44]

Answer:

$x = 1 + \sqrt5, x = 1 - \sqrt5$

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: $ax^2 + bx + c = 0$

Quadratic Formula: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

Given our Equation: $g(x) = x^2 - 2x - 4$

a = 1
b = -2
c = -4

Plug the values into the equation and solve.

<h3>Solve</h3>

$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}$
$x = \frac{2\pm\sqrt{4 +16}}{2}$
$x = \frac{2\pm\sqrt{20}}{2}$
$x = \frac{2\pm\sqrt{4 * 5}}{2}$
$x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}$
$x = \frac{2\pm2\sqrt5}{2}$
$x = 1 + \sqrt5, x = 1 - \sqrt5$

7 0

2 years ago