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gulaghasi [49]
2 years ago
5

Marie wants to space markers evenly along a 5-mile race course. She puts a marker at the start line. how far apart should the ma

rkers be?
Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
4 0
Well how many markers does she have

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What is the perimeter of the kite?<br> a.44<br> b.140
Andreyy89

Answer:

B.) 140 is your answer for your problem

5 0
2 years ago
What is the diameter of a circle with area of 113.04 square cm. use 3.14?<br><br><br> pls fast
galina1969 [7]

Answer:

diameter of a circle = 12cm

Step-by-step explanation:

Area of a circle = πr²

113.04 cm² = πr²

First, search for radius (r) :-

r = √(113.04/π)

r = 6 cm

As diameter is equals to 2×radius

The diameter of a circle = 2 × 6cm

Final answer = 12 cm

3 0
2 years ago
Read 2 more answers
1. Oblicz:
dem82 [27]

Step-by-step explanation:

1. Oblicz:

a) Liczbę o 15% mniejszą od 60

b) Liczbę, której 15% stanowi 60

c) Jakim procentem 60 jest 15

d) O ile %większa jest 60 od 15

2. Kasia kupiła buty na wyprzedaży przecenione o 20%. Ich cena początkowa to 180 zł. W domu sprzedała je siostrze zarabiając na tym 10% wartości. Ile zapłaciła Kasi siostra za buty?

3. Liczba, którą powiększymy o 20% daje nam 30. Jaka to była liczba?

4. Za dwie książki zapłacono 42 zł. Ile kosztuje droższa z nich, jeżeli jedna jest o 25 % tańsza od drugiej?

5 0
2 years ago
The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Artemon [7]

Answer:

P(X \geq 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N(\mu=73,\sigma^{2}=3^{2})

The z score probability distribution is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 73

           \sigma = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X \geq 74)

 P(X \geq 74) = P( \frac{X-\mu}{\sigma} \geq \frac{74-73}{3} ) = P(Z \geq 0.33) = 1 - P(Z < 0.33)

                                               =  1 - 0.62930 = 0.3707                  

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

3 0
3 years ago
F(x) = x2 + 4x – 5 is x = -2.
Likurg_2 [28]
If im correct it would be -2(2)+4(-2)-5 which is -4-8-5 which would be -17
5 0
3 years ago
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