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amid [387]
3 years ago
8

20 points!! Type the correct answer in the box. Use numerals instead of words. What value of n makes the equation true? -1/5n+7=

2 n =
Mathematics
1 answer:
vredina [299]3 years ago
6 0

Hey there! :)

Answer:

\huge\boxed{n = 25}

-1/5n + 7 = 2

Start by subtracting 7 from both sides:

-1/5n + 7 - (7) = 2 - (7)

-1/5n = -5

Multiply both sides by the reciprocal of -1/5, or -5.

(-5) · (-1/5n) = (-5) · (-5)

n = 25

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On Sunday, Sheldon bought 4 1/2 kg of plant food. He used 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plant
VladimirAG [237]

Answer:

a) 2\frac{7}{12} kg of plant food did Sheldon have left.

b) She need is \frac{43}{12} kg and she don't have enough to left.

Step-by-step explanation:

Given : On Sunday, Sheldon bought 4\frac{1}{2} kg of plant food. He used 1\frac{2}{3} kg on his strawberry plants and used \frac{1}{4} kg for his tomato plants.

To find :

a) How many kilograms of plant food did Sheldon have left? Write one or more equations to show how you reached your answer.

Solution :

Sheldon bought plant food 4\frac{1}{2}=\frac{9}{2} kg.

He used strawberry plants 1\frac{2}{3}=\frac{5}{3} kg.

He used tomato plants \frac{1}{4} kg

Kilograms of plant food did Sheldon have left is given by,

L=\frac{9}{2}-(\frac{5}{3}+\frac{1}{4})

L=\frac{9}{2}-\frac{23}{12}

L=\frac{54-23}{12}

L=\frac{31}{12}

L=2\frac{7}{12}

Therefore, 2\frac{7}{12} kg of plant food did Sheldon have left.

b) Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will he need? Does he have enough left to do so?

Solution :

Sheldon wants to feed his strawberry plants 2 more times.

i.e. Strawberry plants used is 2(\frac{5}{3})=\frac{10}{3} kg.

His tomato plants one more time i.e. \frac{1}{4} kg.

Total plant she need is \frac{10}{3}+\frac{1}{4}=\frac{43}{12}

As \frac{31}{12}

No she don't have enough to left.

4 0
3 years ago
As shown in the graph, ΔGHI ≅ ΔG'H'I', since this is a vertical shift, and ΔG'H'I' ≅ ΔG''H''I'', since this is a horizontal shif
vredina [299]

Answer:

I believe its B. so sorry if I'm wrong

7 0
3 years ago
Read 2 more answers
The first three steps of completing the square to solve the quadratic equation x^2+4x-6=0 are shown below.
ad-work [718]
Take the sqrt of both sides of <span>(x+2)^2=10:

x+2 = plus or minus sqrt(10)

Solve for x:  x = -2 plus or minus sqrt(10)

Evaluate x:  x = -2 + sqrt(10)  AND  x = -2 - sqrt(10)       (answers)

</span>
5 0
3 years ago
Workers have been down the street installing two blinking red lights in front of the fire station. The two lights are always tur
daser333 [38]

Answer:

After 88 seconds, they will blink together.

Step-by-step explanation:

Time after which the first light blinks = 8 seconds

Time after which the second light blinks = 22 seconds

Initially, both the lights blink together.

To find:

The time at which they will blink together again.

Solution:

Let us have a look at the time after which each light will blink.

First light will blink after:

8 s, 16 s, 24 s, 32 s, 40 s, 48 s, 56 s, 64 s, 72 s, 80 s, <em>88 s</em>, 96 s, 104 s, ......

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It can be seen that common time is 88 second, at which the both will blink together.

So, the answer is <em>88 s.</em>

<em></em>

This answer can also be computed by taking the LCM (Least Common Multiple) of both the numbers i.e. 8 and 22.

Using the factorization method:

8=\underline{2}\times 2\times 2

22=\underline{2}\times 11

Common is 2.

Therefore the LCM will be:

2\times 2\times2\times 11 = \bold{88}

So, the answer is <em>88 s.</em>

5 0
3 years ago
Triangle TRI has a base of m centimeters and a height of n centimeters. Rectangle RECT has a length of n centimeters and a width
hram777 [196]
The area of the triangle is 
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7 0
3 years ago
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