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Schach [20]
2 years ago
6

\sqrt{12}\times \sqrt{8}

Mathematics
1 answer:
saul85 [17]2 years ago
5 0

Answer:

9.8

Step-by-step explanation:

sqrt(12)=3.5 × sqrt(8)=2.8 = 9.8

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A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find
Veseljchak [2.6K]

Answer:

Approximately 68.5\; \rm mm.

Step-by-step explanation:

Convert the angle of this sector to radians:

\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}.

The formula s = r\, \theta relates the arc length s of a sector of angle \theta (in radians) to the radius r of this sector.

In this question, it is given that the arc length of this sector is s = 36\; \rm mm. It was found that \theta = 2.22 radians. Rearrange the equation s = r\, \theta to find the radius r of this sector:

\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}.

The perimeter of this sector would be:

\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}.

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Choose the best answer that represents the property used to rewrite the expression.
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