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Work out 5/25+2/50+7/100

bixtya [17]

Answer:

The answer is 31/100

Step-by-step explanation:

5/25 + 2/50 + 7/100 = 31/100

8 0

2 years ago

Shelly ran 2 1/4 miles Lynne ran 3 1/8 Miles WhobRan Farther and by how much

ValentinkaMS [17]

Lynne ran farther and by 7/8 miles

You can tell Lynne ran further because she ran 3 whole miles while shelly only ran 2 whole miles. Now you have to subtract to see how much Lynne had ran more.

You found a common denominator between 8 and 4. 4 can turn into 8. so you multiply 4x2 and 1x2 to get a mixed number of 2 2/8

Now you have to turn 3 1/8 because you cannot subtract 2/8 from 1/8. You can turn the fraction into 2 9/8 because there are 8 pieces in a whole.

2 9/8 - 2 2/8 = 0 7/8

Hope this helps! :)

6 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

3 years ago

Select the true statement. A. Neither function is even. B. Only function f is even. C. Only function g is even. D. Both function

astraxan [27]

Answer:

The answer is "Option C".

Step-by-step explanation:

The graph of the even function will have both ends pointed in the same direction, while the graph of the odd function will have both ends pointed inside the reverse way. Furthermore, as the y-axis approaches, and also regular expression graph becomes symmetric. The graph of an unusual function, on either hand, is symmetric around the origin and also has rotational symmetry around the origin. They could see that the graph of function g meets a function requirement by looking at it. That graph of function f, but on the other hand, is not symmetric about its y-axis, implying that function f is not even. As both a result, g is a function that is even.

5 0

3 years ago

Read 2 more answers

Please help,I really need it

dalvyx [7]

What do you need help with?

5 0

3 years ago