Since you are giving no information whatsoever, the formula could be:
S = (1/2)g.t², where s is the distance, 9 =9.8 m/s² and t = time
S = (1/2).(9.8)(2.2)² ans S= 23.7 meters
This expression cannot be simplified, as you cannot add or subtract variables raised to different exponents.
25% = 0.25
70*0.25 = 17.50
Subtract 17.50 from 70
70-17.50 = $52.50
180- 113 = 67
180- 67= 113
<5= 67
<2=113
Answer:
See below.
Step-by-step explanation:
Again, another great question!
This should be under physics, as it involves Work = Force * Distance. As Anne pushes the wheelbarrow with a force of 70 Newtons with respect to an angle of 50 degrees horizontal, the horizontal force is 70( cos 50 ). The distance over which the work is done is 25 meters, so work should be -
Work = ( 70( cos 50 ) )( 25 ),
Work = ( About ) 1124.87 Joules
<u><em>The work done when Anne pushes the wheelbarrow a distance of 25 meters, is 1124.87 Joules</em></u>
