X+Y+Z=2+(-3)+(-4)=-5
That's your answer, lovely~
Given :
An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g of an alloy containing 92% copper.
To Find :
How many grams of copper are in the resulting mixture what percentage of the resulting mixture is copper.
Solution :
Mass of copper in 50 gm alloy =
.
Mass of copper in 78 gm alloy =
.
Total mass of copper, ( 6 + 76.44 ) gm = 82.44 gram.
Percentage of copper in resulting mixture :

Hence, this is the required solution.
i think the answer would be C
For this problem, 0.25 in = 50 m. So
11 in = (11 in) • (50/0.25 m/in) = 2200 m
Alternatively, if 0.25 in = 50 m, that means 1 in = 200 m. So 11 in = 11 (200 m) = 2200 m.