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3 years ago

What is the intermediate step in the form (x + a)2 = b as a result of completing the

Mathematics

1 answer:

nadezda [96]3 years ago

4 0

Answer:

y=(x-1)^2 -1

Step-by-step explanation:

If you put it in the form (x-a)^2=b

The answer will be (x-1)^2=1

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The average weekly salary of two employees is $5250. One makes $500 more than the other. Find their salaries.

irga5000 [103]

Answer: thier salaries are $5000 and $5500

Step-by-step explanation:

Let the average weekly salary of one employee be =x

And that of the other employee be = x+500

Such that if thier average of their salaries= $5250

So, their total salary= $5250 x 2=10,500

The equation to solve each employee salary becomes

x+x+500=10,500

2x+500=10,500

2x=10,500-500

2x=10,000

x=10,000 /2

x= first employee salary =$5000

second employee = x+500 =$5500

3 0

3 years ago

What is the slope of the line in the graph?

Bingel [31]

Answer:

The slope equals the rise divided by the run:

7 0

3 years ago

Solve the inequality and graph its solution...<br> 3+v≤-9

xxTIMURxx [149]

Answer:

v≤-12, and the graph is left 12

Step-by-step explanation:

6 0

3 years ago

Triangle ABC is such that AB = 3cm , BC = 4cm , angle ABC = 120 and BAC = theta : Write down in terms of theta , and expression

lakkis [162]

1)inside the triangule is 180º .There are 3 angules, one with 120º, theta and
angle ACB, lets call it x.

x + theta + 120 = 180
x + theta= 180-120
x + theta= 60
x= 60- theta
angle ACB= 60- theta

8 0

4 years ago

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

7 0

3 years ago