87.5
Tall. /. Shadow
3 / 1.74=. X /. 50.75
Cross multiply
152.25= 3x
Divide by 3
X= 87.5
Answer:
(- 1, 2 )
Step-by-step explanation:
Given the 2 equations
- 3x - 5y = - 7 → (1)
- 4x + 5y = 14 → (2)
Add the 2 equations term by term to eliminate y , that is
- 7x + 0 = 7
- 7x = 7 ( divide both sides by - 7 )
x = - 1
Substitute x = - 1 into either of the 2 equations and solve for y
Substituting into (1)
- 3(- 1) - 5y = - 7
3 - 5y = - 7 ( subtract 3 from both sides )
- 5y = - 10 ( divide both sides by - 5 )
y = 2
solution is (- 1, 2 )
Substitute
, so that
. Then the ODE is equivalent to

which is separable as

Split the left side into partial fractions,

so that integrating both sides is trivial and we get








Given the initial condition
, we find

so that the ODE has the particular solution,

Answer:
Step-by-step explanation:
y - 2 = -2(x - 3)
y - 2 = -2x + 6
y = -2x + 8