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olga_2 [115]
3 years ago
10

Can someone help me please?

Mathematics
2 answers:
gregori [183]3 years ago
6 0
So we would need to add them all up then divide by 9 because of how much we added.



after adding and then dividing (addition first) we should get 133
Nookie1986 [14]3 years ago
4 0

Answer:

133

Step-by-step explanation:

Add all the numbers then divide by how many numbers there are

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Find the quotient of (5+4i)/(6+8i) ans express in simplest forms
atroni [7]

Answer:

Your correct answer is 31/50 + -4/25 i

Step-by-step explanation:

5+4i/6+8i = 31/50 + -4/25 i

8 0
3 years ago
Find the missing side. Round to the nearest tenth. y=?
avanturin [10]
I believe it’s 140 I rounded it and got 140 so it should work
8 0
2 years ago
Can someone please help me??? And please be sure of ur answer :)
Rina8888 [55]

Answer:

1. is the last one.

2. is the 3rd one.

3. is the first one.

4. is the 2nd one.

Step-by-step explanation:

What you do is you have to get the letter by itself and it all depends on the less than or greater than signs.

For #1. -m+8>6. What you do is you minus 8 from both sides to get -m>-2. You still have a -m so you need to divide both sides by a -1. (<em><u>one thing to remember is when you divide by a negative you have to switch the sign.</u></em>) So your answer will be m<2. That will make the last graph the answer.

For #2. -2p< or equal to -10. What you do is divide by -2. and you need to remember to switch the sign. So your answer is p> or equal to 5.

You will do the same for the other two equations but your answers are.

#1. is the last one graph.

#2. is the 3rd one graph.

#3. is the first one graph.

#4. is the 2nd one graph.

3 0
4 years ago
I need help with my final study guide
Citrus2011 [14]
21) Since all angles = 180,
180=66 + 79 + (43 + x)
Subtract (66 + 79) from both sides, you’d get
35= 43 + x
subtract 43 from both sides and x = -8

6 0
3 years ago
Solve for P. <br><br> S=A+1/2PL
Dovator [93]

9514 1404 393

Answer:

  (b)  P = 2(S -A) ÷ L

Step-by-step explanation:

Undo what is done to P.

  S=A+\dfrac{1}{2}PL\qquad\text{given}\\\\S-A = \dfrac{1}{2}PL\qquad\text{subtract $A$}\\\\\dfrac{2}{L}(S-A)=P \qquad\text{multiply by $\dfrac{2}{L}$}\\\\\boxed{P=\dfrac{2(S-A)}{L}}

5 0
3 years ago
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