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2 years ago

Answer Are SSS,ASA,AAS,SAS Not enough Information PLEASE HELP ME PLEASE

Mathematics

1 answer:

Leokris [45]2 years ago

3 0

Answer:

1.SAS

2. AAS

3.SAS

4.SSS

5.SSS

6.SSS

Step-by-step explanation:

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Help me please!!! Find the distance between the points (-3,-1) and (5,-1)

Stella [2.4K]

Answer:

D = 8

Step-by-step explanation:

$d= \sqrt{(5-(-3))^2+(-1-(-1))^2} \\d= \sqrt{(8)^2+(0)^2} \\d= \sqrt{64+0} \\d= \sqrt{64} \\d= 8$

6 0

3 years ago

Tracy wants to buy some pies for her sisters and she has a budget of $82 to spend on $5

Shkiper50 [21]

Answer:

5 of each item is how much she should buy

Step-by-step explanation:

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3 years ago

What is 23/20 as a mixed number

cupoosta [38]

Step-by-step explanation:

this is an improper fraction to make it mixed you have to find how many 20s are in 23

yea only one

so 1 is the whole number

then it is 1 3/20

you can again make it improper by multiplying denominator by 1 and adding 3

7 0

2 years ago

Read 2 more answers

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 117.7-cm and a standard dev

Andre45 [30]

Answer:

Required probability is 0.9748

Step-by-step explanation:

given data

mean $\mu$ = 117.7-cm

standard deviation $\sigma$ = 2.2-cm

sample size n = 29

solution

we consider here random variable which represents here length of rod= x

so get here first z that is express as

$Z = \dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

put here value with x value 118.5-cm

$Z = \dfrac{118.5-117.7}{\dfrac{2.2}{\sqrt{29}}}$

Z = 1.9582

p value is 0.9748

so required probability is 0.9748

7 0

3 years ago

Find a counterexample to show that the statement is false. Assume all sets are subsets of a universal set U = {1, 2, 3, 4, 5}. (

natka813 [3]

Answer:

For subsets A={1,2},B={2,3},C={1,2 5} of U = {1, 2, 3, 4, 5}.

A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

Step-By-Step Explanation:

U = {1, 2, 3, 4, 5}.

A={1,2}

B={2,3}

C={1,2 5}

For the Left Hand Side

B-C={3}

A ∪ (B − C)= {1,2} ∪ {3} ={1,2,3}

Likewise, the Right Hand Side:

(A ∪ B)={1,2,3}

(A ∪ C)={1,2,5}

(A ∪ B)- (A ∪ C)= {1,2,3}-{1,2,5}={3}

Since, {1,2,3} ≠ {3}, A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

7 0

2 years ago