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labwork [276]
3 years ago
13

A carnival game has the possibility of scoring 50 points, 75 points, or 150 points per turn. The probability of scoring 50 point

s is 60%, 75 points is 30%, and 150 points is 10%. The game operator designed a simulation using a random number generator to predict how many points would be earned for a turn.
Integer Value Points Frequency
0 - 5 50 55
6 - 8 75 32
9 150 13


10. What is game’s expected value of points earned for a turn?
(SHOW WORK)
Mathematics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

The game’s expected value of points earned for a turn is 71.

Step-by-step explanation:

Here we know that:

Points     Frequency

50           55

75            32

150          13

Here points earned is a random variable.

We need to find its expected value,

Finding Expected value:

Expected value of a random variable is its mean value. So we will first find the mean value of points earned per turn from the table we are given.

Total number of turns = sum of frequencies

= 55 + 32 + 14 = 100

Total points earned = 50(55) + 75(32) + 150(13)

= 7100

Expected value of points earned for a turn = Mean value of points

= Total points/no. of turns

= 7100/100

= 71

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we know that

If (x-8) is a factor of the function f(x)=-2x^{3}+17x^{2}-64

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x=8 is a root of the function f(x)

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f(8)=-2(8)^{3}+17(8)^{2}-64

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<u>the answer is</u>

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4 years ago
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ikadub [295]

Answer:  \bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}

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3 years ago
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