<span>a) Intervals of increase is where the derivative is positive
b) </span> <span>Intervals of decrease is where the derivative is negative. </span>
c) <span>Inflection points of the function are where the graph changes concavity that is the point where the second derivative is zero </span>
<span>d)
Concave up- Second derivative positive </span>
<span>Concave down- second derivative negative </span>
f(x) = 4x^4 − 32x^3 + 89x^2 − 95x + 31
<span>f '(x) = 16x^3 - 96x^2 + 178x - 95 </span>
<span>f "(x) = 48x^2 - 192x + 178 </span>
<span>By rational root theorem the f '(x) has one rational root and factors to: </span>
<span>f '(x) = (2x - 5)*(8x^2 - 28x + 19) </span>
<span>Using the quadratic formula to find it's two irrational real roots. </span>
<span>The f "(x) = 48x^2 - 192x + 178 only has irrational real roots, use quadratic formula which will be the inflection points as well.</span>
Answer 3.14
Step-by-step explanation:
Area= pi*r^2
Circumference=2*pi*r
Area=C^2/4pi= 6.28^2/4*pi which ='s 3.13841
Answer:
I think the answer is C 72 grams
Step-by-step explanation:
What do you mean can you show a pic
Answer:
The other acute angle = 33 1/3°
Step-by-step explanation:
Hard to read the angle measure.
one acute angle = 56 2/3° x = the second acute angle
Find the other acute angles.
The two acute angles sum in a right triangle = 90°
56 2/3° + x° = 90°
x = 90 - 56 2/3
x = 89 3/3° - 56 2/3°
x = 33 1/3°
