The approximate amount of water that remains in the tub after the 6 spherical balls are placed in the tub are 3479.12 in³.
<h3>What is the approximate amount of water that remains in the tub?</h3>
The first step is to determine the volume of the cylinder.
Volume of the tub = πr²h
Where:
- r = radius = diameter / 2 = 18/2 = 9 inches
- h = height
- π = 3.14
3.14 x 9² x 20 = 5086.8 in³
The second step is to determine the volume of the 6 balls.
Volume of a sphere= 4/3πr³
r = diameter / 2 = 8/2 = 4 inches
6 x (3.14 x 4/3 x 4³) = 1607.68 in³
Volume that remains in the tub = 5086.8 in³ - 1607.68 in³ = 3479.12 in³
To learn more about the volume of a sphere, please check: brainly.com/question/13705125
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1. Write in y=mx+b Form 8x+2y=18. 8x+2y=18 8 x + 2 y = 18. The slope-intercept form is y=mx+b y = m x + b , where m m is the slope and b b is the y-intercept.
2. Simple and best practice solution for 7x-y=35 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand,
Answer:
b = 16
Step-by-step explanation:
16*x + b*x + 4 = 0
Solving for x we get:
x₁,₂ = - b ± √ b² - 4*a*c ] / 2*a (1)
If we take a look to the square root
√ b² - 4*4*16 = √ b² - 256
if we make √ b² - 256 = 0
b² = 256 ⇒ b = 16
Then equation (1) becomes:
x₁,₂ = ( - 16 ± 0 ) / 32
x = - 1/2
These two integers are -6 and -7
She didnt divide the whole problem by 3 it would be x+3=8 then the rest of the work
