Answer: A because its always A
Step-by-step explanation:
Answer:
D is the answer
Step-by-step explanation:
For a: g(x) = 1 when x = 1, for f(x) 1^2 - 2(1) + 2 = 1, a is true.
For b: Both functions do have all real numbers for their domain, b is true
For c: the y-intercept of g(x) is x = 0, for f(x), it is 0^2 - 2(0) + 2 = 2, c is true
For d: g(3) = 7, f(3) = 3^2 - 2(3) + 2 = 5, d is false.
Answer:
-3(4x+3)+5x (Given) 1/2 (6k+10)+5k (given)
-12x-9+5x (distribution) 3k+5+5k (distribution)
-12x+5x-9 (associative) 3k+5k+5 (associative)
-7x-9 (Combine like terms) 8k+5 (combine like terms)
Step-by-step explanation:
15.
Make sure to follow the order of operations.
because the y-intercept is 3, you'll place your first point up 3 on the y-axis (so (0, 3)). From there you can use your slope to graph the rest
Because your slope is -6, rise over run tells you it's pretty much -6/1, thus, from the point you placed on the y-axis you go down 3 places, and to the right 1. This makes your next point (-3, 1). For your last point you use your rise over run vice versa and go up 6 places, and to the left 1. This point would be (8, -1). If you connect these 3 points you'll have a pretty good graph
