(0,0) and (6,0)
First we subtract 18x from both sides
3x²-18x=0
Factor out a 3x
3x(x-6)=0
This means that x is either 0 or 6
Answer:
the first 3 consecutive numbers
x, x +1, x +2 = 270
x+x+1+x+2 =270
3x +3 =270
collect like terms
3x =270 -3
3x =267
divide both sides by 3
x =89
Answer:
A) -2
Step-by-step explanation:
The form is indeterminate at x=0, so L'Hopital's rule applies. The resulting form is also indeterminate at x=0, so a second application is required.
Let f(x) = x·sin(x); g(x) = cos(x) -1
Then f'(x) = sin(x) +x·cos(x), and g'(x) = -sin(x).
We still have f'(0)/g'(0) = 0/0 . . . . . indeterminate.
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Differentiating numerator and denominator a second time gives ...
f''(x) = 2cos(x) -sin(x)
g''(x) = -cos(x)
Then f''(0)/g''(0) = 2/-1 = -2
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I like to start by graphing the expression to see if that is informative as to what the limit should be. The graph suggests the limit is -2, as we found.
C. y=4 through isolating of the variable
<span>Slope intercept form is always y=mx+b where your
m is your slope and your b is your y-intercept. Knowing this we first need to put your equation into slope intercept form. to do this all we have to do is subtract everything except why across an equal sign to get y=-6x+4. Now all you have to do is figure out what the 'b' is to know that the y-intercept is 4</span>