Question

Check all that apply. If csc0=13/5, then:

Answer 1

I hope this helps you

Answer 2

Answer:  B) sin θ = 5/13    and    D) tan θ = 5/12

Step-by-step explanation:

$\csc\theta=\dfrac{r}{y}=\dfrac{13}{5}$

Use Pythagorean Theorem: x² + y² = r² to calculate x = 12

$\sin \theta=\dfrac{y}{r}=\dfrac{5}{13}\qquad \qquad \qquad \csc \theta=\dfrac{r}{y}=\dfrac{13}{5}\\\\\\\\\cos \theta=\dfrac{x}{r}=\dfrac{12}{13}\qquad \qquad \qquad \sec \theta=\dfrac{r}{x}=\dfrac{13}{12}\\\\\\\\\tan \theta=\dfrac{y}{x}=\dfrac{5}{12}\qquad \qquad \qquad \cot \theta=\dfrac{x}{y}=\dfrac{12}{5}$