After 24 hours, 35.4% of the initial dosage remains on the body.
<h3>What percentage of the last dosage remains?</h3>
The exponential decay is written as:

Where A is the initial value, in this case 2.8mg.
k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:

Replacing all that in the above formula, and evaluating in x = 24 hours we get:

The percentage of the initial dosage that remains is:

If you want to learn more about exponential decays:
brainly.com/question/11464095
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1) 2x-1 or x=1/2
2) 5a-16 or a=16/5
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