I need help quick!!!!!!

Mathematics

1 answer:

Fofino [41]3 years ago

5 0

The answer is y = 2x = 2.

POINT 1: (0,0)

POINT 2: (2, 6)

2 × 2 = 4 + 2 = 6

POINT 3 : (3, 8)

3 × 2 = 6 + 2 = 8

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On a separate piece of graph paper, graph y = -|x| + 1; then click on the graph until the correct one appears.

a_sh-v [17]

|x| is tricky but maybe I can tell you so that it's clear 4ever.

You have to look at when what's inside the absolute value iszero. In this case x=0. That easy. Then, you have to split the cases:

For x>= 0, you have y = -x+1,

For x<=0, you have y = -(-x) + 1 = x+1, because abs(x)=-x, if x<=0.

Notice that x=0 is included in either case, because |x| is continuous.

Then plot each line choosing a couple of points, notice that for one case you should choose x=-1, -2, or x=0, but not positive values, and the other way for the case with x>=0.

Best

3 0

3 years ago

Read 2 more answers

What is the distance between tow points (1,5)(-8,4)

Degger [83]

Answer:

$\displaystyle d = \sqrt{82}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Identify

Point (1, 5)

Point (-8, 4)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(-8-1)^2+(4-5)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(-9)^2+(-1)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{81+1}$
[√Radical] Add: $\displaystyle d = \sqrt{82}$

6 0

3 years ago

A cone has a radius of 8 inches and a height of 12 inches.What is the exact volume of the cone?

Cerrena [4.2K]

$The\ volume\ of\ the\ cone:V=\frac{1}{3}\pi r^2H\\\\where\\r-radius\\H-height\\----------------\\\\r=8\ in\ and\ H=12\ in\\\\therefore\\\\V=\frac{1}3{\pi\cdot8^2\cdot12=\frac{1}{\not3_1}\cdot\frac{\not12^4}{1}\cdot64\pi=4\cdot64\pi=\boxed{256\pi\ (in^3)}$