Answer:
No, it's not equivalent
Step-by-step explanation:
Try and solve the one with the bracket first. Expand 8(15-r) : 8x15 and 8x-r = 120 - 8r
Therefore, the equation can now be written as:
6r-r + 120-8r + 23-6
Rearrange the like terms together and solve the equation:
6r-r-8r + 120+23-6 = -3r + 137
M = 6 - 5n hope this helps
Answer:
5sqrt3
Step-by-step explanation:
Using the pythagorean theorem, we have a^2+4^2=9^2
a^2 + 16 = 81
a^2 = 75.
a = sqrt75.
75 = 25*3. 25 is a perfect square, so sqrt75 = 5sqrt3
<h3>
Answer: Choice B. 1/3p</h3>
This is assuming that p is not in the denominator. To make it more clear that p is not in the denominator, I recommend you write (1/3)p.
Taking 1/3 of a number is the same as dividing by 3.
Example:
27/3 = 9
27*(1/3) = 9
