I think it's 74 because 3 has the factor :1,3
53 has the factor: 53,1
73 has the factor:1 ,73
74 has the factor:1,74,2,37
Answer:
990 ways
Step-by-step explanation:
The total number of automobiles we have is 11.
Now, what this means is that for the first position , we shall be selecting 1 out of 11 automobiles, this can be done in 11 ways( 11C1 = 11!/(11-1)!1! = 11!/10!1! = 11 ways)
For the second position, since we have the first position already, the number of ways we can select the second position is selecting 1 out of available 10 and that can be done in 10 ways(10C1 ways = 10!9!1! = 10 ways)
For the third position, we have 9 automobiles and we want to select 1, this can be done in 9 ways(9C1 ways = 9!/8!1! = 9 ways)
Thus, the total number of ways the first three finishers come in = 11 * 10 * 9 = 990 ways
Answer:
C
You just split the equation, as the brackets are both same. If you take (x-6) out, it will leave you with 3x+8.
Therefore, (x-6)(3x+8) is the answer.
Answer:
The answer is A.
if im wrong im truly sorry
