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3 years ago

Does someone know how the correct answer?? I need help

Mathematics

2 answers:

anyanavicka [17]3 years ago

8 0

Answer:

(-2,1)

Step-by-step explanation:

add 3 to x,(-5 + 3 = -2) and subtract 2 from y,(3 - 2 = 1)

yulyashka [42]3 years ago

5 0

Answer:

55.23

Step-by-step explanation:

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Y=3x-1<br> Help pleaseeeeee

nata0808 [166]

Answer:

y=3x-1

Step-by-step explanation:

Not enough context

Hope this helps!

3 0

2 years ago

Given the figure below, find the values of x and z.

charle [14.2K]

Answer:

I think z = 89 and I don’t know x

8 0

3 years ago

The question is in the image below.

sineoko [7]

Answer:

The Recursive Formula for the sequence is:

$\:a_n=\frac{1}{5}\left(a_{n-1}\right)$ ; a₁ = 125

Hence, option D is correct.

Step-by-step explanation:

We know that a geometric sequence has a constant ratio 'r'.

The formula for the nth term of the geometric sequence is

$a_n=a_1\cdot r^{n-1}$

where

aₙ is the nth term of the sequence

a₁ is the first term of the sequence

r is the common ratio

We are given the explicit formula for the geometric sequence such as:

$a_n=125\left(\frac{1}{5}\right)^{n-1}$

comparing with the nth term of the sequence, we get

a₁ = 125

r = 1/5

Recursive Formula:

We already know that

a₁ = 125

r = 1/5

We know that each successive term in the geometric sequence is 'r' times the previous term where 'r' is the common ratio.

i.e.

$a_n=ra_{n-1}$

Thus, substituting r = 1/5

$\:a_n=\frac{1}{5}\left(a_{n-1}\right)$

and a₁ = 125.

Therefore, the Recursive Formula for the sequence is:

$\:a_n=\frac{1}{5}\left(a_{n-1}\right)$ ; a₁ = 125

Hence, option D is correct.

3 0

3 years ago

For an arithmetic sequence, a35=57. If the common difference is 5. Find a1 and the sum of the first 61 terms.

Flauer [41]

$\displaystyle\bf\\a_{35}=57\\r=5\\----\\a_1=?\\S_{61}=?\\----\\Solve:\\1)\\a_1=a_{35}-(35-1)\times r=57-34\times 5=57-170=-113\\\boxed{\bf a_1=-113}\\\\$

$\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276$

$\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}$

8 0

3 years ago

What is the x-intercepts of the graph of y = 12x-5x-2

devlian [24]

Hey there!

First, we see that it's already written in slope intercept, y = mx + b where m is the slope and b is the y intercept, we just need to simplify the like terms on the right. We have:

y = 12x-5x-2
y = 7x - 2

Now that we have it in slope intercept form, whenever we have an x intercept, since it is crossing the x axis, there's no y value. We plug in 0 for y:

0 = 7x - 2
2 = 7x
2/7 = x

The x intercept is (2/7, 0)

Hope this helps!

6 0

3 years ago