Answer:
The answer is the first one ⇒ AAS
Step-by-step explanation:
∵ DB ⊥ AC
∴ m∠DBA = m∠DBC = 90° ⇒ (1)
∵ m∠A = m∠C ⇒ (2) given (from figure)
∵ DB is a common side in the two Δ ⇒ (3)
From (1) , (2) and (3)
∴ Δ ABD is congruent to Δ CBD ⇒ AAS
Answer:
8
Step-by-step explanation:
DCB and ABC are right angles
DCB = 90 = 7x + 34
If 7x + 34 = 90, then 7x = 56 and x = 8
Hope this helps :)
Rise over run would be your slope sooo your slope is one that what I got
Step-by-step answer:
Answer to problems of this kind is the reciprocal of the harmonic mean of the time required.
We need to find the average of the speeds, not the average of the time.
The respective speeds are 1/3 and 1/4.
The average of the speeds is therefore (1/3+1/4)/2 = 7/24 (harmonic mean of the time taken).
The time required is therefore the reciprocal of the unit speed,
T = 1/(7/24) = 24/7 = 3 3/7 minutes, or approximately 3.43 minutes.
