9514 1404 393
Answer:
3a by 4a
Step-by-step explanation:
For dimensions L and W, the area and perimeter are ...
A = LW = 12a^2
P = 2(L+W) = 14a
Using the second equation, we can find L:
L +W = 7a . . . . . divide by 2
L = 7a -W
Substituting into the area formula gives the quadratic ...
(7a -W)(W) = 12a^2
W^2 -7aW +12a^2 = 0 . . . . arrange in standard form
(W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)
Then we have the two solutions ...
W = 3a, L = 4a
W = 4a, L = 3a
The rectangle dimensions are 3a by 4a.
Area
=3*2/2+6*1/2+3*6/2+(6+7)*6/2
=54
Okay so this is your equation; 17=221/x
all you need to do is multiply 221 by 17 and you'll have your answer. I hope this helps!
Answer: 3
Step-by-step explanation:
Given
For 
to be true, the domain is given by observing the graph of two i.e. 
. In this range 
is greater than 
.
From the above domain largest integer that can satisfy the condition is 3.
