![\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvertical%20parabola%20vertex%20form%20with%20focus%20point%20distance%7D%20%5C%5C%5C%5C%204p%28y-%20k%29%3D%28x-%20h%29%5E2%20%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5Cqquad%20%5Cstackrel%7Bfocus~point%7D%7B%28h%2Ck%2Bp%29%7D%5Cqquad%20%5Cstackrel%7Bdirectrix%7D%7By%3Dk-p%7D%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%20%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22p%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22p%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)

something noteworthy is that the squared variable is the "x", thus the parabola is a vertical one, the "p" value is negative, so is opening downwards, and the h,k is pretty much the origin,
vertex is at (0,0)
the focus point is "p" or 5 units down from there, namely at (0, -5)
the directrix is "p" units on the opposite direction, up, namely at y = 5
the focal width, well, |4p| is pretty much the focal width, in this case, is simply yeap, you guessed it, 20.

Given, 6 batteries for £2.79
(They are of same type, so each of them are of same cost. )
~Simply divide the total price of 6 batteries by 6 to get the price of each battery,




Thus, cost of each battery is <u>£</u><u> </u><u>0</u><u>.</u><u>4</u><u>6</u><u>5</u><u> </u><u>(</u><u>ans)</u>
Answer:
$3577.20
Step-by-step explanation:
You can save 11% of your income each month, so in 12 months, you can save ...
12×0.11×$2710 = $3577.20
Answer:
Part 1) 
Part 2) 
Part 3) m∠K=61°
Part 4) m∠L=119°
Part 5) m∠M=61°
Step-by-step explanation:
we know that
In a parallelogram opposite angles and opposite sides are congruent and consecutive angles are supplementary
Part 1) Find the side MN
we know that
MN≅KL ----> by opposite sides
we have

therefore

Part 2) Find the side KN
we know that
KN≅LM ----> by opposite sides
we have

therefore

Part 3) Find the measure of angle K
we know that
m∠K+m∠N=180° ----> by consecutive interior angles
we have
m∠N=119°
substitute
m∠K+119°=180°
m∠K=180°-119°
m∠K=61°
Part 4) Find the measure of angle L
we know that
m∠L≅m∠N ----> by opposite angles
we have
m∠N=119°
therefore
m∠L=119°
Part 5) Find the measure of angle M
we know that
m∠M≅m∠K ----> by opposite angles
we have
m∠K=61°
therefore
m∠M=61°
D is the answer that is graphed.