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Advocard [28]
3 years ago
5

Suppose two rectangles are similar with a scale factor of 2. What is the ratio of thier areas? Explain.

Mathematics
1 answer:
Anton [14]3 years ago
3 0

Answer:

4

Step-by-step explanation:

From the question,

Since both rectangle has a scale factor of 2,

L₁/L₂ = 2

Where L₁ and L₂ are the length of the first and second rectangle respectively

L₁ = 2L₂................ Equation 1

Also,

W₁/W₂ = 2............ Equation 2

Where W₁ and W₂ are the Width of the first and second rectangle respectively

W₁ = 2W₂

Area of a rectangle = Length × width

Area of first rectangle = L₁×W₁ = 2L₂×2W₂ = 4L₂W₂

Area of second rectangle = L₂×W₂= L₂W₂

The ratio of area = Area of the first rectangle/Area of the second rectangle = 4L₂W₂/L₂W₂ = 4

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Step-by-step explanation:

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===========================

we want to find all possible values of α+β+γ when <u>tanα+tanβ+tanγ = tanαtanβtanγ</u><u> </u>to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =  \tan( \alpha )  \tan( \beta )  \tan( \gamma )  -  \tan( \gamma )

factor out tanγ:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =   \tan( \gamma ) (\tan( \alpha )  \tan( \beta ) -  1)

divide both sides by tanαtanβ-1 and that yields:

\rm\displaystyle   \tan( \gamma ) =  \frac{ \tan( \alpha )  +  \tan( \beta ) }{ \tan( \alpha )  \tan( \beta )    - 1}

multiply both numerator and denominator by-1 which yields:

\rm\displaystyle   \tan( \gamma ) =   -  \bigg(\frac{ \tan( \alpha )  +  \tan( \beta ) }{ 1 - \tan( \alpha )  \tan( \beta )   } \bigg)

recall angle sum indentity of tan:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( \alpha  +  \beta )

let α+β be t and transform:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( t)

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\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm k\pi )

therefore <u>when</u><u> </u><u>k </u><u>is </u><u>1</u> we obtain:

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isolate -α-β to left hand side and change its sign:

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isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ 0  }

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