The limit is x---->4-
The negative show that x approaches from the left
Now
As x approaches 4 from the left ... Means This number should be less than 4 (<4) but really close to 4.
Let's pick a Number
Say 3.99
Substitute this... You have
3.99/3.99-4
3.99/-0.01
If we choose x to be 3.999
we will have
3.999/-0.001
Notice the pattern... As x approaches 4 from the left... This limit will approach NEGATIVE INFINITY
Why?
As you approach 4 from the left... 3.9,3.99,3.999... You notice that the denominator becomes negative and EXTREMELY SMALL... and when you divide by an extremely small Number..... You'll get a relatively HUGE VALUE(You can try this... Use a calc... Divide any number of choice by a very small number... say.. 0.0000001.... You'll get a huge result
In our case... The denominator is negative... So it Will Approach a very Huge Negative Number
Hence
Answer.. X WILL APPROACH NEGATIVE INFINITY.
Vertical asymptotes are the zeroes of the denominator of a function
The denom. is x-4
Equate to zero to get the asymptote
x-4=0
x=4
Hence... There will be a vertical asymptote at x=4.
Have a great day!
Answer:
The inches in height will be 18 inches.
Step-by-step explanation:
Okay so we know that the original width is 4 inches and she enlarged that to 12 inches
So what we first have to do is find out how much did the photograph "grow" per se. To find this we have to divide 12 by 4. 12 divided by 4 = 3.
So, the width of the photograph grew "times 3" inches
Now whatever you do to the width you have to do to the height. In this case, what is "3 times" 6 (which is the height). 3 times 6 = 18 inches
So in simpler words 12 divided 4 = 3 x 6 = 18 inches
The inches in height will be 18 inches.
Jill has a square with a width of 12 inches, and a height of 18 inches.
Have a wonderful day!
Answer with Step-by-step explanation:
We are given that an expression
We have to find domain restriction of the given function.
Domain restriction means : It is that value of x when substitute in function then function will not defined.
It means it is that values which makes denominator zero.
From given function we can see that
When substitute g=0 then it makes denominator zero.
Hence, the function is not defined at g=0
Substitute g=4
Then, it makes denominator zero.
Hence, function is not defined at g=4
Substitute g=2
Then,it makes denominator zero.
Hence, function is not defined at g=2
Therefore, the function is defined for all values of g except g=0, g=2 and g=4
