answer:
you just have to shrink it down to 4cm then to 2cm
i wish i could help out more, but i would need to have access to the form
hopefully, this helps anyhow :)
good luck
have a great day !!
Answer:
-4y^2+2y+3
Step-by-step explanation:
(2y+1)-4y^2+2
2y+1-4y^2+2
-4y^2+2y+1+2
-4y^2+2y+3
Average (mean) = (sum of all the data) / (# of data)
sum of all the data = (average)(# of data)
Thus for 100 students with an average of 93,
sum of all data = (93)(100) = 9300
and for 300 students with an average of 75,
sum of all data = (75)(300) = 22500
Therefore you would expect the overall average to be
(9300 + 22500) / (100 + 300) = 79.5 %
Now if there are x # of advanced students and y # of regular students, then
x + y = 90 (total # of students) and 93x + 75y = 87(x + y) (overall average)
The second equation can be simplified to x - 2y = 0
Subtracting the two equations yields
x = 60 and y = 90
Therefore you would need 60 advanced and 30 regular students.
16: B; irrational number, real
17: C; whole, integer, rational, real
18: B; real, rational, integer
Answer:
3(6+4) ._. hope this helps
