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Karolina [17]
3 years ago
7

Write six hundred fifty-eight and twenty-nine thousandths in standard form​

Mathematics
2 answers:
Pepsi [2]3 years ago
7 0

Answer:

658.029

Step-by-step explanation:

hope this helps  (´▽`ʃ♡ƪ)

adelina 88 [10]3 years ago
4 0

did 57urgkg zucfhuiiiiiiiii

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Mark reduce the size of a photo to a height of 4 inches. What is the new width if it was originally 16 inches tall and 8 inches
uranmaximum [27]

Answer:

Step-by-step explanation:

new height is ¼ of original height

new width = ¼×8 = 2 inches

4 0
3 years ago
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I need an explanation for the problem 4v2=-12v-9. I don't understand why it factors into 4v+3 and 4v+3
kirza4 [7]

Answer:

The factors are 2v+3,2v+3.

The factors are not 4v+3,4v+3

Step-by-step explanation:

Equation is 4v^2=-12v-9.

This equation can be written as follows:

4v^2+12v+9=0

Here,

12v=6v+6v

Therefore,

4v^2+6v+6v+9=0\\2v(2v+3)+3(2v+3)=0\\(2v+3)(2v+3)=0

So, the factors are 2v+3,2v+3.

The factors are not 4v+3,4v+3

7 0
3 years ago
Which of the following represents the distance
Lunna [17]

Answer:

D.  d = sqrt( ( x2-x1)^2 + (y2-y1)^2)

C.   d = sqrt( ( x1-x2)^2 + (y1-y2)^2)

B.  d = sqrt( (|x2-x1|^2 + |y2-y1|^2)

Step-by-step explanation:

Given two points (x1, y1) and (x2,y2)  we can find the distance using

d = sqrt( ( x2-x1)^2 + (y2-y1)^2)

The order of the terms inside the square doesn't matter

d = sqrt( ( x1-x2)^2 + (y1-y2)^2)

When we are squaring are term, we can take the absolute value before we square and it does not change the value

d = sqrt( (|x2-x1|^2 + |y2-y1|^2)

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3 years ago
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