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3 years ago

Help please?! This is graphing rational functions

Mathematics

1 answer:

guapka [62]3 years ago

7 0

Answer:

D: (-∞,2) (2,∞)

R:(-∞,0),(0,∞)

Step-by-step explanation:

From the graph we can see that the graph is approaching 0 horizontally and 2 vertically but not crossing so we can assumer these are the asymptotes. So the domain goes all the way from -∞ to 2 but does not cross 2 so we have to stop there and create another bracket for 2 to ∞. It is the same process for the range but in the y direction.

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What is 8 3/4 ÷ 2 7/8 (show ur work)

xxMikexx [17]

Answer:

see below:-

Step-by-step explanation:

$\displaystyle{8 \frac{3}{4} \div 2 \frac{7}{8} }$

Convert the mixed fractions into improper fractions.

$\displaystyle{ \frac{8 \times 4 + 3}{4} \div \frac{8 \times 2 + 7}{8} }$

$\displaystyle{ \frac{32 + 3}{4} \div \frac{16 + 7}{8} }$

$\displaystyle{ \frac{35}{4} \div \frac{23}{8} }$

$\displaystyle{ \frac{35}{4} \times \frac{8}{23} }$

$\displaystyle{ \frac{35}{ \cancel4} \times \frac{ \cancel8 {}^{2} }{23} }$

$\displaystyle{ \frac{35 \times 2}{23} }$

$\displaystyle{ \frac{70}{23} }$

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6 0

2 years ago

Read 2 more answers

What is the following product? (4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago

Given that (-8,- 7) in on the graph of f(x), find the corresponding point for the fuction f(x -4)

kiruha [24]

The point (x1,y1) on the graph of f(x) is the point (x1-a,y1) for the function
f(x+a)

(-8,-7)=(x1,y1)→x1=-8, y1=-7
f(x-4)=f(x+a)→a=-4

(x1-a, y1)=(-8-(-4), -7)=(-8+4, -7)=(-4,-7)

The corresponding point for the fuction f(x -4) is (-4,-7)

8 0

3 years ago

Rearrange w= 3(2a + b) - 4 to make a the subject

Angelina_Jolie [31]

Answer:

$\boxed{a = \frac{w}{ 6} - \frac{b}{2} + \frac{2}{3} }$

Step-by-step explanation:

$Solve \: for \: a: \\ = > w=3(2a+b)-4 \\ \\ w=3(2a+b)4 \: is \: equivalent \: to \: 3(2a+b)-4= w: \\ = > 3(2a+b) - 4=w \\ \\ Expand \: out \: terms \: of \: the \: left \: hand \: side: \\ = > (3 \times 2a) + (3 \times b) - 4 = w \\ = > 6a+3b - 4=w \\ \\ Subtract \: 3b - 4 \: from \: both \: sides: \\ = > 6a + 3b - 4 - (3b - 4)=w - (3b - 4) \\ = > 6a = w - 3b + 4 \\ \\ Divide \: both \: sides \: by \: 6: \\ = > \frac{ \cancel{6}a}{ \cancel{6}} = \frac{w - 3b + 4}{6} \\ = > a = \frac{w}{6} - \frac{3b}{6} + \frac{4}{6} \\ = > a = \frac{w}{ 6} - \frac{b}{2} + \frac{2}{3}$

8 0

3 years ago

Can anyone show how they solved this really need help

charle [14.2K]

The total number of degrees in would be 720. By subtracting all other angles you will find x.

720-129-105-135-130-95=126

X=126

6 0

3 years ago

Read 2 more answers