The one-to-one functions g and h are defined as follows.

Mathematics

1 answer:

never [62]3 years ago

3 0

Answer:

g^−1(7) = 6

h^−1(x) = x/2 + 3/2

(h^−1 ∘ h)(3) = 3

Step-by-step explanation:

g(6) = 7

Then

g^−1(7) = 6

h(x) = 2x - 3

Isolate x:

2x = h(x) + 3

x = h(x)/2 + 3/2

Replace x with h^−1(x) and h(x) with x:

h^−1(x) = x/2 + 3/2

We know that:

(h^−1 ∘ h)(x) = x

then:

(h^−1 ∘ h)(3) = 3

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