Answer:
Step-by-step explanation:
By applying tangent rule in the given right triangle AOB,
tan(30°) = 


By applying tangent rule in the given right triangle BOC,
tan(60°) = 
OC = BO(√3)
OA + OC = AC

2√3(BO) = 60
BO = 10√3
OC = BO(√3)
OC = (10√3)(√3)
OC = 30
By applying tangent rule in right triangle DOC,
tan(60°) = 
OD = OC(√3)
OD = 30√3
Since, BD = BO + OD
BD = 10√3 + 30√3
BD = 40√3
≈ 69.3
The answer for your question is 12/15
Answer:
<em>d) The equation of the line passing through the points </em>

Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given points are ( 0, -4) and (2 ,0)
slope of the line

<u><em>Step(ii):</em></u>-
The equation of the line passing through the point ( 0,-4) and having slope



2 ( y +4) = -x
2 y + 8 = -x
2 y = - x - 8


<u><em>Final answer:-</em></u>
<em>The equation of the line passing through the points </em>

<em></em>
<em></em>
Its c.
If you will substitute those numbers to the pair of equations, both will be true.
1=-3+4
1=3-2
Answer:
1) 0.00274
2) 0.872
3) 0.00240
Step-by-step explanation:
1) 365/(365×365) = 1/365
= 0.002739726027
= 0.00274 (3 sf)
2) (364/365)^50
= 0.8718182573
= 0.872 (3 sf)
3) [365 × (364^48)]/(365^50)
= 0.002401685062
= 0.00240 (3 sf)