The cost to enter the fair is $9. Ride cost $5 each write the equation to represent this problem

Buddy guy!!, has anyone noticed that mos thanks have bats literally lots of there names r like dome7

pshichka [43]

Answer:

yes i noticed that

Step-by-step explanation:

4 0

3 years ago

Given LMNP ∼ QRST, find RS.

creativ13 [48]

I can’t solve right now but if you know cross multiplication i can set up the equation for you

27/45=x/25
now cross multiply and get your answer :)

6 0

3 years ago

Read 2 more answers

Maths watch help me please thank you

Dovator [93]

Answer:

71 %

Step-by-step explanation:

Paper 1 :

65% of 120 = 0.65 X 120 = 78

Paper 2 :

80% of 80 = 0.8 X 80 = 64

Total Percentage:

Add the two scores 78 + 64 = 142

Add the what it was out of 120 + 80 = 200

Use (Score / Total marks available) X 100

(142 / 200) X 100 = 71

3 0

3 years ago

NEED HELP!! Scenario #1: You flip a coin and roll a six sided die. What is the probability that you will flip heads and roll a n

leva [86]

Scenario #1:

Flipping a coin and rolling a die are independent events, so the combined probability is the product of the individual probabilities.

Flipping a coin: There are two different possible outcomes, heads and tails. You are interested in heads. You are interested in 1 outcome out of 2.

p(heads) = 1/2

Rolling a die: There are 6 different possible outcomes, the numbers 1, 2, 3, 4, 5, and 6. You are interested in a number greater than 2, so your desired outcomes are 3, 4, 5, 6, which means 4 different desired outcomes out of 6.

p(die toss greater than 2) = 4/6 = 2/3

Combined probability:

p(heads followed by number greater than 2) =

= p(heads) * p(die toss greater than 2)

= 1/2 * 2/3

= 1/3

Scenario #2:

There are 4 colors on the spinner. For each color on the spinner, the die can land on one of 6 numbers. 4 * 6 = 24. There are 24 different combined outcomes.

You are interested in blue OR 6. Six outcomes have blue and a number from 1 to 6. Then if the spinner lands in any of the other 3 colors, each one has one outcome of 6 with that color. The total number of desired outcomes is 6 + 3 = 9.

Number of desired outcomes: 9

Number of possible outcomes: 24

p(blue or 6) = 9/24 = 3/8

Final Question:

The scenario that gives you better odds is Scenario #2 since 3/8 > 1/3.

4 0

3 years ago

Explain how to use Pascal's Triangle to expand the binomial (3x-4y)^11

Mars2501 [29]

The solution to the binomial expression by using Pascal's triangle is:

$\mathbf{=177147x^{11}-2598156x^{10}y +17321040x^9y^2-69284160x^8y^3+184757760x^7y^4}$

$\mathbf{-344881152x^6y^5+459841536x^5y^6-437944320x^4y^7+291962880x^3y^8}$

$\mathbf{-129761280x2y^9+34603008xy^{10}-4194304y^{11}}$

<h3>How can we use Pascal's triangle to expand a binomial expression?</h3>

Pascal's triangle can be used to calculate the coefficients of the expansion of (a+b)ⁿ by taking the exponent (n) and adding the value of 1 to it. The coefficients will correspond with the line (n+1) of the triangle.

We can have the Pascal tree triangle expressed as follows:

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

--- --- --- --- --- --- --- --- --- --- --- --- --- --- ---

From the given information:

The expansion of (3x-4y)^11 will correspond to line 11.

Using the general formula for the Pascal triangle:

$\mathbf{(a+b)^n = c_oa^nb^0 + c_1 a^{n-1}b^1+c_{n-1}a^1b^{n-1}+c_na^0b^n}$

The solution to the expansion of the binomial (3x-4y)^11 can be computed as:

$\mathbf{=177147x^{11}-2598156x^{10}y +17321040x^9y^2-69284160x^8y^3+184757760x^7y^4}$

$\mathbf{-344881152x^6y^5+459841536x^5y^6-437944320x^4y^7+291962880x^3y^8}$

$\mathbf{-129761280x2y^9+34603008xy^{10}-4194304y^{11}}$

Learn more about Pascal's triangle here:

brainly.com/question/16978014

#SPJ1

5 0

2 years ago