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brilliants [131]
3 years ago
8

Solve the inequality. Graph the solution set and write it in interval notation. .

Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0

Answer:

 -4

Step-by-step explanation:

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Use Long Division to answer number 4. Please show all work!​
skelet666 [1.2K]

Answer:

2x² + 3x + 4 + (17x + 9) / (x² − 4)

Step-by-step explanation:

Start by setting up the division.  Make sure to write all the coefficients, even the zero ones.

x² + 0x − 4 | 2x⁴ + 3x³ − 4x² + 5x − 7

Start by dividing the first term of the dividend (2x⁴) by the first term of the divisor (x²).  That's 2x²; it'll be the first term in quotient.  Multiply the divisor by 2x²:

2x⁴ + 0x³ − 8x²

Subtract that from the first three terms of the dividend:

3x³ + 4x²

Drop down the next term from the dividend, and start the process all over again.

3x³ + 4x² + 5x

When you finish, the quotient will be 2x² + 3x + 4, and the remainder will be 17x + 9.

4 0
3 years ago
What is sin(A)?<br> 13<br> 12<br> A<br> 5<br> sin(A) =
eimsori [14]

Answer:

sin A = 12/13

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

 sin theta = opposite side/ hypotenuse

sin A = 12/13

6 0
3 years ago
Determine if the given differential equation is exact (e^2y-y cos xy)dx+(2xe^2 y-cos xy+2y)dy=0
rewona [7]
\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy

\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy

The partial derivatives are not equal, so the equation is not exact.
7 0
3 years ago
Find the area. The figure is not drawn to scale.
VMariaS [17]

The figure on the top left is a triangle with base 11 and height 8, for an area of

A_1=\dfrac{11\cdot 8}{2}=44

Immediately below, we have a rectangle with dimensions 11 and 9, for an area of

A_2=11\cdot 9=99

Moving to the right, we have a parallelogram with base 9 and heght 11, which again has height

A_3=11\cdot 9=99

Finally, the rightmost figure is a triangle with base 8 and height 9, for a total of

A_4=\dfrac{8\cdot 9}{4}=36

Sum these areas and you'll get the total area

4 0
3 years ago
bongo had a balance of $345.28 in his checking account. During the week amounts: $65.08, $24.50, and $118.95. He then made a dep
vichka [17]

Answer: 192.75

Step-by-step explanation:

I am answering your question assuming that the three amounts were checks that were written out during the week.

Beginning balance = 345.28

Subtract the total amount of the checks (65.08 + 24.50 + 118.95 = 208.53)

345.28 - 208.53 = 136.75

Next, add the amount of the deposit. 136.75 + 56.00 = 192.75

8 0
3 years ago
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