Answer:
= 9,593.1 Joules
Explanation:
Heat absorbed by water is equivalent to heat released by copper.
Heat absorbed is given by;
Q = mcΔT
where m is the mass, c is the specific capacity and ΔT is the change in temperature.
Therefore;
Since dnsity of water is 1 g/mL, and specific heat capacity is 4.18 J/g°C while the change in temperature is (75-24) = 51°C.
Heat absorbed by water = 45 g × 4.18 J/g°C × 51
= 9,593.1 Joules
Therefore, the heat released by copper is 9,593.1 Joules
Only the amount of gas is held constant.
Explanation:
The given reaction equation is as follows.
The value of 
= 59.1 kJ/mol
We know that
,
or, 
= -(\frac{59.1 kJ/mol}{(8.314 \times 10^{-3} kJ/mol.K \times 310 K))}[/tex]
= -22.93
or, 
= 
![K_{sp} = [Ba^{2+}][ SO_{4}^{2-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BBa%5E%7B2%2B%7D%5D%5B%20SO_%7B4%7D%5E%7B2-%7D%5D)
Therefore, ![[Ba^{2+}] =\sqrt{K_{sp}}](https://tex.z-dn.net/?f=%5BBa%5E%7B2%2B%7D%5D%20%3D%5Csqrt%7BK_%7Bsp%7D%7D)
= 
= 
Therefore, we can conclude that the value of ![[Ba^{2+}]](https://tex.z-dn.net/?f=%5BBa%5E%7B2%2B%7D%5D)
in the intestinal tract is .
The answer is oxidation.
That is in the redox fueling reaction,
succinate + NAD ↔fumarate + NADPH, the succinate molecule is undergoing oxidation.
As succinate molecule is providing electrons to NAD, so that it can be reduced from NAD to NADPH. So it is losing electrons and undergoing oxidation.
So the answer is oxidation.
This question uses weighted averages.
Since the average mass of element A is 63.6 amu and the only two isotopes are 63 and 65,
63.6 = x% * 63 + (1-x%) * 65
If you don't want to calculate this (like me), you can look at the answer choices.
If it was 100% A-63, the weight would be 63. Cross off D.
If it was 50/50, the weight would be 64. Cross off C.
So since the weighted average is 63.6, you would expect there to be more A-63 than A-65, so B is the only answer that makes sense.
