Answer:
Oxidation occurs at the anode: Fe(s) | Fe2+(aq) half cell. (ii) Reduction occurs at the cathode: Ag(s) | Ag+(aq) half cell. Oxidation occurs at the anode: Pt | Sn2+(aq), Sn4+(aq) half cell. (iii) Electrons flow from the anode to the cathode: from the Pt(s) → Ag(s) electrode.
Here, Heat is transferring directly from a place to another without direct contact, or particles in series this kind of transfer of heat is known as "Radiation"
In short, Your Answer would be Option C
Hope this helps!
Answer
PubChem CID/molecular formula
Explanation:
Cesium bromide
PubChem CID 24592
Molecular Formula CsBr or BrCs
Synonyms CESIUM BROMIDE 7787-69-1 Caesium bromide Cesiumbromide Cesium bromide (CsBr) More...
Molecular Weight 212.81 g/mol
Component Compounds CID 260 (Hydrogen bromide) CID 5354618 (Cesium)
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Answer:could u expand on the question
Explanation:
Answer:
760 mmHg
Explanation:
Step 1: Given data
- Partial pressure of nitrogen (pN₂): 592 mmHg
- Partial pressure of oxygen (pO₂): 160 mmHg
- Partial pressure of argon (pAr): 7 mmHg
- Partial pressure of the trace gas (pt): 1 mmHg
Step 2: Calculate the atmospheric pressure
Since air is a gaseous mixture, the atmospheric pressure is equal to the sum of the gases that compose it.
P = pN₂ + pO₂ + pAr + pt = 592 mmHg + 160 mmHg + 7 mmHg + 1 mmHg = 760 mmHg
