Answer:
3. 3.45×10¯¹⁸ J.
4. 1.25×10¹⁵ Hz.
Explanation:
3. Determination of the energy of the photon.
Frequency (v) = 5.2×10¹⁵ Hz
Planck's constant (h) = 6.626×10¯³⁴ Js
Energy (E) =?
The energy of the photon can be obtained by using the following formula:
E = hv
E = 6.626×10¯³⁴ × 5.2×10¹⁵
E = 3.45×10¯¹⁸ J
Thus, the energy of the photon is 3.45×10¯¹⁸ J
4. Determination of the frequency of the radiation.
Wavelength (λ) = 2.4×10¯⁵ cm
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:
100 cm = 1 m
Therefore,
2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm
2.4×10¯⁵ cm = 2.4×10¯⁷ m
Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m
Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:
Wavelength (λ) = 2.4×10¯⁷ m
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
v = c / λ
v = 3×10⁸ / 2.4×10¯⁷
v = 1.25×10¹⁵ Hz
Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.
Answer:
0.486atm is the pressure of the cylinder
Explanation:
1 mole of Pb(NO₃)₂ descomposes in 4 moles of NO2 and 1 mole of O2. That is 1 mole descomposes in 5 moles of gas.
To find the pressure of the cylinder, we need to find moles of gas produced, and using general gas law we can determine the pressure of the gas:
<em>Moles Pb(NO₃)₂ and moles of gas:</em>
3.31g * (1mol / 331g) = 0.01 moles of Pb(NO₃)₂.
That means moles of gas produced is 0.05 moles.
<em>Pressure of the gas:</em>
Using PV = nRT
P = nRT/V
<em>Where P is pressure (Incognite)</em>
<em>V is volume (2.53L)</em>
<em>R is gas constant (0.082atmL/molK)</em>
<em>T is absolute temperature (300K)</em>
And n are moles of gas (0.05 moles)
P = 0.05mol*0.082atmL/molK*300K / 2.53L
P = 0.486atm is the pressure of the cylinder
<span>c] The golfer sent the golf ball flying toward the cup to score a hole in one.</span>
