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RSB [31]
3 years ago
14

2x18-5+15%5=32 Insert parentheses to make each equal true

Mathematics
1 answer:
Colt1911 [192]3 years ago
3 0

Answer:

( 2×8) - [ ( 5 + 15 ) ÷ 5] = 32

Step-by-step explanation:

According to the scenario, computation of the given data are as follows,

Given equation = 2x18-5+15/5=32

First we multiply first two letters,

then ( 2 × 18) = 36

Now, we add 5 and 15 then divide it by 5,

So, ( 5 + 15 ) ÷ 5 = 20 ÷ 5 = 4

Now we subtract 4 from 36,

Then 36 - 4 = 32

Hence the correct parentheses = ( 2×8) - [ ( 5 + 15 ) ÷ 5] = 32

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2 years ago
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A trapezoid is shown. The lengths of the bases are 4 and 8. The height of the altitude is 4. What is the area of the trapezoid?
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It would be 24 units^2 because the middle is 16 and the two triangles are 4 each
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3 years ago
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Use two different methods to find an explain the formula for the area of a trapezoid that has parallel sides of length a and B a
evablogger [386]

Answer:

Formula of Trapezoid:

A = (a + b) × h / 2

The formula can be derived in different ways. for now, we have discussed two ways:

1. By using the formula of a triangle

2. By dividing into different sections

Step-by-step explanation:

1. By using the formula of a triangle

One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.

Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.

The image is attached below.

Connect vertices P and R with a diagonal.

Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).

Its area is

S1=\frac{1}{2} *PQ*RM

Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).

Its area is

S2=\frac{1}{2} *SR*PN

Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.

They both are equal to the altitude of the trapezoid h.

Therefore, we can represent areas of our two triangles as

S1=\frac{1}{2}*PQ*h

S2=\frac{1}{2}*SR*h

Adding them together, we get the area of the whole trapezoid:

S=S1+S2=\frac{1}{2} (PQ+SR)h,

which is usually represented in words as "half-sum of the bases times the altitude".

2. By dividing into different sections

Trapezoid PQRS is shown below, with PQ parallel to RS.

Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)

We are going to derive the area of a trapezoid by dividing it into different sections.

If we drop another line from Q, then we will have two altitudes namely PT and QU.

Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)

From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that

=> A_{PQRS} = (\frac{ah}{2}) + b_{1}h + \frac{ch}{2}

Simplifying, we have

=>A= \frac{ah+2b_{1+C} }{2}

Factoring we have,

=> A_{PQRS} = (a+ 2b_{1} + c)\frac{h}{2}  \\= > {(a+ b_{1} + c) + b_{1} }\frac{h}{2}

 But, a+ b_{1} + c  is equal to b_{2}, the longer base of our trapezoid.

Hence, A_{PQRS}= (b_{1} + b_{2} )\frac{h}{2}

We have discussed two ways by which we can derive area of a trapezoid.

Read to know more about Trapezoid

brainly.com/question/4758162?referrer=searchResults

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1 year ago
Which expression is equivalent to (–3y – x) – (5y – 8x)? –8y – 8x –8y 7x 2y – 7x 8y 8x.
IRINA_888 [86]

The expression is equivalent to -8y + 7x.

Given

Expression; (-3y - x) - (5y - 8x)

<h3>How to find the equivalent expression?</h3>

To find the equivalent expression multiply the expression and add and simplify.

Then,

The expression is equivalent to;

 (-3y - x) - (5y - 8x)

-3y - x - 5y + 8x

-8y + 7x

Hence, the expression is equivalent to -8y + 7x.

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A survey about the student government program at a school finds the following results:
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A total of 440 students took part in the survey. Each student makes up 0.8181818182% of the central angle of the circle graph. You get to this number by dividing 360 degrees by 440 students. Then you simply multiply this number by 110 students (who liked the program).

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3 years ago
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