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Mazyrski [523]
3 years ago
12

If you expect the target firm to grow at your calculated annual growth rate for the next four years (2021- 2024) and then beyond

grow at an annual rate of 2%, , what is the value of the entire target firm assuming a weighted average cost of capital (WACC) of 10.5%
Business
1 answer:
frez [133]3 years ago
7 0

Answer:

The question is incomplete, so I looked for a similar one:

FCF 2018 = ($4,923,478 - $1,033,930 + $605,752) - ($2,173,000 + $605,752) - ($8,501,348 - $7,600,543) = $4,495,300 - $2,778,752 - $900,805 = $815,743

FCF 2019 = ($5,960,124 - $1,251,626 + $1,239,239) - ($2,580,000 + $1,239,239) - ($7,210,800 - $5,905,791) = $5,947,737 - $3,819,239 - $1,305,009 = $823,849

FCF 2020 = ($5,998,321 - $1,259,647 + $239,895) - ($1,903,500 + $239,895) - ($5,975,324 - $4,116,364) = $4,978,569 - $2,143,395 - $1,858,960= $976,214

average annual growth rate 2018 - 2020 = {[(823,849 - 815,743)/815,743] + [(976,214 - 823,849)/823,849]} / 2 = (0.99% + 18.49%) / 2 = 9.74%

FCF 2021 = $976,214 x 1.0974 = $1,071,297

FCF 2022 = $1,071,297 x 1.0974 = $1,175,642

FCF 2023 = $1,175,642 x 1.02 = $1,199,154

first we must calculate the terminal value in 2022 = $1,199,154 / (10.5% - 2%) = $14,107,699

the firm's current value = $1,071,297/1.105 + $1,175,642/1.105² + $14,107,699/1.105² = $13,486,312

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Tju [1.3M]
Its A hope this helpsss
7 0
3 years ago
A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius
anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

T^2 \alpha  a^3

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 \times 10^8 \ km

Therefore, T^2 = ca^3

c= \dfrac{365^2}{(1.496 \times 10^8)^3}

c = 3.9791 \times 10^{20} \ day^2/km^3

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

T^2 = ca^3

a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}

a^3 = 2.9092 \times 10^{27}

a= \sqrt[3]{2.9092 \times 10^{27}}

a = 1.4275 \times 10^9 \ km

However, the velocity for a perihelion = 10.18 km/s

Using the formula

v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})} to calculate the radius, we have:

G = 6.674 \times 10^{-11}

M = 1.989\times 10^{30} \ kg

r = perihelion

v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})

(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30}  ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})

7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}

\dfrac{2}{r} = 1.4824 \times 10^{-12}

r = \dfrac{2}{1.4824 \times 10^{-12}}

r = 1.349 \times 10^{12}

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)

1.349 \times 10^{12}  -  1.425 \times 10^{12}= -  1.425 \times 10^{12} (e)

-7.6\times 10^{10}= -  1.425 \times 10^{12} (e)

\dfrac{-7.6\times 10^{10}}{-  1.425 \times 10^{12}}=  (e)

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

r = 1.425 \times 10^{12} ( 1 + 0.0533)

r = 1.50 \times 10^{12} \ m

to nautical miles, we have:

r = 1.50 \times 10^{12} \times 0.00054  \ nautical \ mile

radius of aphelion \mathbf{r = 8.10 \times 10^8} nautical miles

In respect to the value of a( i.e 1.4275 \times  10^9 \ km)

the body of the solar system is Saturn

5 0
3 years ago
The following information summarizes the standard cost for producing one metal tennis racket frame at Spaulding Industries. In a
astra-53 [7]

Answer:

Actual Price paid for materials = $4.2136 \times 2,200 = $9,270

Actual price per unit = $4.2136

Explanation:

Provided information,

Standard Material per unit = $4

Total cost = $8,400

Standard Quantity = $8,400/$4 = 2,100 units

Provided Material Price variance = $470 unfavorable = - $470

= (Standard Price - Actual Price) \times Actual Units

Material Quantity Variance = $400 Unfavorable = - $400

= (Standard Quantity - Actual Quantity) \times Standard Rate

Using Material Quantity Variance

- $400 = (2,100 - Actual Quantity) \times $4

-$400/$4 = 2,100 - Actual Quantity

Actual Quantity = 2,100 + 100 = 2,200 units

Now, putting this value in Material Price Variance we have,

- $470 = ($4 - Actual Price) \times 2,200

-$470/2,200 = $4 - Actual Price

- $0.214 = $4 - Actual Price

Actual Price = $4 + $0.2136 = $4.2136

Final Answer

Actual Price paid for materials = $4.2136 \times 2,200 = $9,270

Actual price per unit = $4.2136

8 0
4 years ago
These are selected account balances on December 31, 2020. Land (location of the office building) $97000 Land (held for future us
Artyom0805 [142]

Answer:

$937,000

Explanation:

Calculation to determine the total net amount of property, plant, and equipment that will appear on the balance sheet

Land (location of the office building) $97000

Add Office Building 675000

Add Equipment 457000

Add Office Furniture 135000

Less Accumulated Depreciation (427000 )

Total Net Amount $937,000

Therefore the total net amount of property, plant, and equipment that will appear on the balance sheet is $937,000

4 0
3 years ago
Personal, payroll, medical, and operational are all what types of information
Zolol [24]
Personal , payroll, medical, and operational are all types of sensitive informations. 
Which means that this type of information is usually guarded and protected against unwarranted disclosure

hope this helps
8 0
4 years ago
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