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2 years ago

Which equations are perpendicular to the line that passes through (2,1) and (3,4)

Mathematics

1 answer:

REY [17]2 years ago

5 0

9514 1404 393

Answer:

y=(-1/3)x+6
y=(-1/3)x+10

Step-by-step explanation:

The slope of the given line can be found from the slope formula:

m = (y2 -y1)/(x2 -x1)

m = (4 -1)/(3 -2) = 3/1 = 3

The slope of the perpendicular line is the opposite reciprocal of this:

perpendicular slope = -1/m = -1/3

Choices (c) and (d) have x-coefficients that are -1/3. Those are the perpendicular lines.

y=(-1/3)x+6
y=(-1/3)x+10

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Type the correct answer in the box. Round your answer to the nearest integer.

umka21 [38]

Answer:

m∠ADC = 132°

Step-by-step explanation:

From the figure attached,

By applying sine rule in ΔABD,

$\frac{\text{sin}(\angle ABD)}{\text{AD}}=\frac{\text{sin}(\angle ADB)}{AB}$

$\frac{\text{sin}(120)}{35}=\frac{\text{sin}(\angle ADB)}{30}$

sin(∠ADB) = $\frac{30\text{sin}(120)}{35}$

= 0.74231

m∠ADB = $\text{sin}^{-1}(0.74231)$

= 47.92°

≈ 48°

m∠ADC + m∠ADB = 180° [Linear pair of angles]

m∠ADC + 48° = 180°

m∠ADC = 180° - 48°

m∠ADC = 132°

4 0

2 years ago

D is not right its a negative 8 so therefore it would be minus

Ilya [14]

I really dont understant your question. but you are right that negative 8 that it would be minus. In mathematics, a negative number is a real number that is less than zero. Negative numbers represent opposites. If positive represents movement to the right, negative represents movement to the left.

6 0

2 years ago

What is the measure of EFG? A. 88° B. 176° C. 184 D. 272°

Fudgin [204]

Cghfhgsfg sth. Dyjv

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2 years ago

A car costing $24,000 is subject to a sales tax of 8%. If Bindu made a $10,000 down payment on his car, what is the tot amount s

Serggg [28]

Answer:

$15,920

Step-by-step explanation:

4 0

6 months ago

In your lab, a substance's temperature has been observed to follow the function T(x) = (x + 5)3 + 7. The turning point of the gr

kompoz [17]

A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.

t(x)=(x+5)^3+7

dt/dx=3(x+5)^2

d2t/dx2=6(x-5)

dt/dx=0 only when x=-5

However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.

So there is no turning point for this function.

Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.

8 0

3 years ago