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2 years ago

ASAP I really need help please!

Mathematics

2 answers:

slava [35]2 years ago

7 0

Answer:

I can't see the fine details of the image displaying the weights of the bags but I would assume the heaviest bag is 2(3/4) pounds, being Bag C. The lightest bag is most likely Bag B, being 2(3/8) pounds.

VikaD [51]2 years ago

3 0

Answer:

I can't read the fraction for B

but 2 3/4 is bigger than 2 1/2

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Domingo earns $13 dollars per hour and worked 47.5 hours that week. He is paid

stellarik [79]

Domingo earns 715$ in the week that is his gross income

3 0

2 years ago

PLEASE HELP!!! DUE IN 10 MIN!!!

9966 [12]

Answer:

Option B

Step-by-step explanation:

Surface area of a triangular prism = Area of the triangular sides + Area of the rectangular sides

Area of the triangular sides = 2(Area of the triangular base)

= $2[\frac{1}{2}(\text{Base})(\text{Height})]$

= 10 × 12

= 120 ft²

Area of the rectangular sides = (Perimeter of the triangular side)(Height of the prism)

= (10 + 13 + 13)(15)

= 36 × 15

= 540 ft²

Surface area of the prism = 120 + 540

= 660 square feet

Option B will be the answer.

5 0

2 years ago

What is the next term in this arithmetic sequence? 11, 8, 5, 2,... 0-3 06 05

satela [25.4K]

Answer: the next term is -1

7 0

3 years ago

I give brainliest!!!!

Elza [17]

Answer:

(3，2) i hope this answer will help you

7 0

2 years ago

Read 2 more answers

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago