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Bezzdna [24]
3 years ago
9

ASAP I really need help please!

Mathematics
2 answers:
slava [35]3 years ago
7 0

Answer:

I can't see the fine details of the image displaying the weights of the bags but I would assume the heaviest bag is 2(3/4) pounds, being Bag C. The lightest bag is most likely Bag B, being 2(3/8) pounds.

VikaD [51]3 years ago
3 0

Answer:

I can't read the fraction for B

but 2 3/4 is bigger than 2 1/2

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I need help on my math homework plzz help plzzz
earnstyle [38]

D because 144 /45% is 320 EZ hope i helped you drop a brianlest for me to pls


8 0
3 years ago
A machine paints 34o toy boats im 3/4 of an hour how many boats can he make per hour
leonid [27]
Here, we can set up a proportion:

34 ÷ 3/4 = ? ÷ 1
34*1 = 34
34÷3/4 = the time needed to build one toyboat

34/3/4 = 45.3333333333

45.3 repeating is not a whole number, so we need to approximate. 

45 is the closest whole number, 

So.. a machine can paint 45 toy boats per hour. 

I really hope that helped! :) 

7 0
3 years ago
A dairy produces 256 pints of milk each day. How many gallons of milk is this? (1 gallon
hoa [83]

Answer:

32 gallons

Step-by-step explanation:

c'mon this is simple, but thx for the points

6 0
2 years ago
What is 4x - 2 = 22 8x x =
EleoNora [17]
I think the answer is x = -4.
7 0
3 years ago
The class sizes of elementary school classes in a public school district are normally distributed with an unknown population mea
weqwewe [10]

Answer: (17.14,\ 22.86)

Step-by-step explanation:

The confidence interval estimate for the population mean is given by :-

\overline{x}\pm ME, where \overline{x} is the sample mean and ME  is the margin of error.

Given : Sample mean: \overline{x}=20

The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution : ME=2.86

Now, the confidence interval estimate for the population mean will be :-

20\pm2.86=(20-2.86,\ 20+2.86)=(17.14,\ 22.86)

Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution =  (17.14,\ 22.86)

8 0
3 years ago
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