Describe two ways to fnd the surface area of a rectangular prism.

Mathematics

1 answer:

rodikova [14]3 years ago

3 0

Answer:

1. Through an equation that uses lateral area

2. Through finding the area of each side and taking the sum of all the faces

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Help !! Please I can’t find the answer

SVETLANKA909090 [29]

Answer:

$\large\boxed{r^2=(x+5)^2+(y-4)^2}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have diameter endpoints.

Half the length of the diameter is the length of the radius.

The center of the diameter is the center of the circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the given points (-8, 2) and (-2, 6):

$d=\sqrt{(6-2)^2+(-2-(-8))^2}=\sqrt{4^2+6^2}=\sqrt{16+36}=\sqrt{52}$

The radius:

$r=\dfrac{d}{2}\to r=\dfrac{\sqrt{52}}{2}$

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-2)}{2}=\dfrac{-10}{2}=-5\\\\y=\dfrac{2+6}{2}=\dfrac{8}{2}=4$

$(-5,\ 4)\to h=-5,\ k=4$

Finally:

$(x-(-5))^2+(y-4)^2=\left(\dfrac{\sqrt{52}}{2}\right)^2\\\\(x+5)^2+(y-4)^2=\dfrac{52}{4}\\\\(x+5)^2+(y-4)^2=13$

5 0

3 years ago

Which ordered pair is the solution to the system of equations?

SOVA2 [1]

To find the solution, we use the substitution method.

x+y=-1
x-3y=11

x+y = -1-y
-y

x = -1-y

Now apply the value of x into the other equation.

x-3y=11
-1-y-3y = 11

Combine like terms

-4y -1 = 11
+1 +1
-4y = 12

-4y = 12
-4y/-4 = 12/-4
y = -3

Now, apply the value of Y to one equation to find x.

y = -3

x -3 = -1
+3 +3

x= 2

Now we have the value for both, x and y.
x = 2
y =-3

Final answer: A. (2, −3)

3 0

3 years ago

217 is what percent of 620

Flura [38]

$\sf \dfrac{217}{620} \\ \\ = 0.35 \\ \\ Convert \ the \ decimal \ percent \ by \ multiplying \ 100 \\ \\ 0.35 \times 100 \\ \\ = 35\%$