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Anvisha [2.4K]
3 years ago
8

Determine the largest integer value of xx in the solution of the following inequality. 2x−8≤-19

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

x≤-11/2

Step-by-step explanation:

Hope this helps!

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Romashka [77]

What are you supposed to be doing

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3 years ago
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I need these numbers in scientific notation, please! Thank you!
Shkiper50 [21]

\text{The scientific notation:}\\\\a\cdot10^k\ \text{where}\ 1\leq a

18.4\ m=1.84\cdot10\ m\\\\0.000000000172\ g=0\underbrace{.0000000001}_{10\to}72=1.72\cdot10^{-10}\ g\\\\4292000\ s=4\underbrace{292000}_{\leftarrow6}\ s=4.292\cdot10^6\ s\\\\8.3\ \cdot10^{-4}\ m\\\\1.496\cdot10^8\ m\\\\23.1\cdot10^{-3}\ kg=2.31\cdot10\cdot10^{-3}\ kg=2.31\cdot10^{-2}\ kg

4 0
3 years ago
(-2)2+3 × (-5) <br> please helpe me answer this question
Tpy6a [65]

Answer:

(−2)(2)+(3)(−5)

=−19

Step-by-step explanation:

4 0
3 years ago
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Peyton is collecting data on the lunch habits of students at Hyattsville Middle School. In one class, 14 students bring lunch fr
mart [117]

Answer:

Answer: Around 1000 students would buy a school lunch.

Step-by-step explanation:

We know that in one class, 14 students bring lunch from home, and 20 buy lunch in the school. This will be our sample.

In total we have 20 + 14 = 34 students, this will be our 100%.

The percentage of students that bring lunch from home can be estimated as the quotient between the number of students that bring lunch from home and the total number of students, times 100%.

p1 = (14/34)*100% = 41.18%

And the percentage of students that buy lunch at school can be computed in the same way:

p2= (20/34)*100% = 58.82%

Then, out of the 1700 students in middle school, we can estimate that around 58.82% of them will buy lunch in the school.

Then the exact number will be:

N = (58.82%/100%)*1700 = 1000

Around 1000 students would buy a school lunch.

7 0
2 years ago
In the game of​ roulette, a player can place a ​$8 bet on the number 17 and have a StartFraction 1 Over 38 EndFraction probabili
svp [43]

Answer:

Expected value of the game: -$0.421

Expected loss in 1000 games: $421

Step-by-step explanation:

There are two possible outcomes for the event:

- There is a 1 in 38 chance of winning $280

- There is a 37 in 38 chance of losing $8

The expected value for a single game is:

E(X) = \frac{1}{38}*\$280-\frac{37}{38}*\$8\\E(X)=-\$0.421

The expected value of the game is -$0.421

In 1,000 plays, the expected loss is:

L = 1,000*-\$0.421\\L=-\$421

You would expect to lose $421.

3 0
2 years ago
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