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3 years ago

URGENT!! Please help

Mathematics

1 answer:

7nadin3 [17]3 years ago

7 0

Answer:

The measure of the largest angle is 72º.

Step-by-step explanation:

We will first solve for x. We know that the sum of the interior angles of a triangle is 180º, so 15x + 21x + 24x is equal to 180º. This means that 60x = 180º, so x = 3º. The largest angle is 24x, which is 72º.

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I am an odd number if you take away one I become even

fomenos

$\textbf{Hello !}$ ﾉｼ ✿

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${Answer :}}$

<h2>ODD NUMBER, 7.</h2><h2 />

$\textbf{EXPLANATION :}$

$\textit{Seven, is an odd number. And when you remove the "s" you are left with even. }$

Hope It Helped!

<u>And Tell me if The answer is wrong. . .</u>

<h2><u>Good Luck With Your Assignment!</u></h2><h2 />

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8 0

3 years ago

the regression equation y=-0.414 + 106.55 approximates the percent of people in an audience who finish watching a documentary, y

WARRIOR [948]

Answer:

<em><u>The answer is</u></em>: <u>59%</u>.

Step-by-step explanation:

To calculate the percentage of people who have seen the movie we start from: y = -0.414x + 106.55; and of x = 115; making the appropriate substitutions we would have left: y = -0.414 (115) + 106.55; y = -47.61 + 106.55; y = 58.94, which rounded to exceed 0.5 would be 59%.

<em><u>The answer is</u></em>: <u>59%</u>.

4 0

3 years ago

Read 2 more answers

If x+y=12 and xy=15,find the value of (x^2+y^2)

Mice21 [21]

Answer: $x^2+y^2=\dfrac{105\pm 18\sqrt6}{2}$

<u>Step-by-step explanation:</u>

EQ1: x + y = 12 --> x = 12 - y

EQ2: xy = 15

Substitute x = 12-y into EQ2 to solve for y:

(12 - y)y = 15

12y - y² = 15

0 = y² - 12y + 15

↓ ↓ ↓

a=1 b= -12 c=15

$.\ y=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\.\quad =\dfrac{-(-12)\pm \sqrt{(-12)^2-4(1)(15)}}{2(1)}\\\\\\.\quad =\dfrac{12\pm \sqrt{144-120}}{2}\\\\\\.\quad =\dfrac{12\pm \sqrt{24}}{2}\\\\\\.\quad =\dfrac{12\pm 2\sqrt{6}}{2}\\\\\\.\quad =6\pm \sqrt{6}$

Now, let's solve for x:

$xy=15\\\\x(6\pm\sqrt6)=15\\\\x=\dfrac{15}{6\pm\sqrt6}\\\\\\x=\dfrac{15}{6\pm\sqrt6}\bigg(\dfrac{6\pm\sqrt6}{6\pm\sqrt6}\bigg)=\dfrac{6\pm \sqrt6}{2}$

Lastly, find x² + y² :

$y^2=(6\pm \sqrt6)^2\quad \rightarrow \quad y^2=36\pm 12\sqrt6 +6\quad \rightarrow \quad y^2=42\pm 12\sqrt6$

$x^2=\bigg(\dfrac{6\pm \sqrt6}{2}\bigg)^2\quad \rightarrow \quad x^2=\dfrac{42\pm 12\sqrt6}{4}\quad \rightarrow \quad x^2=\dfrac{21\pm 6\sqrt6}{2}$

$x^2+y^2=\dfrac{21\pm 6\sqrt6}{2}+42\pm 12\sqrt6\\\\\\.\qquad \quad = \dfrac{21\pm 6\sqrt6}{2}+\dfrac{84\pm 24\sqrt6}{2}\\\\\\. \qquad \quad = \dfrac{105\pm 18\sqrt6}{2}$